我想用regex / rlike条件实现连接。但是Hive并没有做不平等加入
select a.col_1, b.col_2
from table1 a left join table2 b
on a.col_1 rlike b.col_2
这实际上有效,但我希望将b.col2中的全文与a.col_1中的字符串相匹配。有没有办法做到这一点?
示例数据集:
**table1**
apple iphone
apple iphone 6s
google nexus
samsung galaxy tab
**table2**
apple
google
nexus
**outcome**
col1 col2
apple iphone apple
apple iphone 6s apple
google nexus google
samsung galaxy tab null
答案 0 :(得分:1)
select col1
,col2
from (select t1.col1
,t2.col2
,count (col2) over (partition by col1) as count_col2
,row_number () over (partition by col1,col2) as rn
from (select *
from table1 t1
lateral view explode(split(col1,'\\s+')) e as token
) t1
left join (select *
from table2 t2
lateral view explode(split(col2,'\\s+')) e as token
) t2
on t2.token =
t1.token
) t
where ( count_col2 = 0
or col1 rlike concat ('\\b',col2,'\\b')
)
and rn = 1
;
+--------------------+--------+
| col1 | col2 |
+--------------------+--------+
| apple iphone | apple |
| apple iphone 6s | apple |
| google nexus | google |
| google nexus | nexus |
| samsung galaxy tab | (null) |
+--------------------+--------+