Question

如何访问内容＆＃39;用feedparser封闭？

<content type="application/xml">
<m:properties xmlns:d="http://schemas.microsoft.com/ado/2007/08/dataservices">
<d:Ref_Key>3a496b6e</d:Ref_Key
</m:properties>
</content>

访问内容＆＃39;

的代码

d = feedparser.parse("http://localhos/odata/standard.odata/Document_Order")
d.entries[0].content[0]

返回类似

的内容

{'base': u'http://localhos/odata/standard.odata/Document_Order', 'type': u'application/xml', 'value': u'', 'language': None}

然后如何获得＆＃39; m：properties＆＃39;和＆＃39; d：Ref_Key＆＃39; ？

Answer 1

似乎feedparser cant pars不是XML标签，建议使用xml.etree.ElementTree

import requests
import xml.etree.ElementTree

url = http://localhost/standard.odata/Document_Visit

req = requests.get(self.url, auth=(self.login, self.password))
root = etree.fromstring(req.text.encode('utf-8'))
entrys = root.findall('{http://www.w3.org/2005/Atom}entry')
properties = content.findall('{http://schemas.microsoft.com/ado/2007/08/dataservices/metadata}properties')
prop_dict = dict()
for prop in properties[0]:
   pritn prop

atom \ xml python feedparser <content>包含访问权限

1 个答案: