使用feedparser访问openSearch：totalResults

Question

如何使用feedparser检索openSearch：totalResults属性？

我有一个博客API结果看起来有点像这样（我已经删除了一些东西以使其紧凑）

 <feed xmlns='http://www.w3.org/2005/Atom'
  xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'
  xmlns:gd='http://schemas.google.com/g/2005'
  gd:etag='W/"CUYMQ348fyp7ImA9WB9UFkU."'>
 <id>tag:blogger.com,1999:blog-blogID.postpostID..comments</id>
 <updated>2007-12-14T17:46:22.077-08:00</updated>
 <title>Comments on Lizzy's Diary: Quite disagreeable</title>  
 <generator version='7.00'
   uri='http://www.blogger.com'>Blogger</generator>
 <openSearch:totalResults>1</openSearch:totalResults>
 <openSearch:startIndex>1</openSearch:startIndex>

目前，我做了类似

的事情

req = urllib.urlopen(url)
urlContent = req.read()            
feed = feedparser.parse(urlContent)
print feed.feed['openSearch_totalResults']

我在上面的代码中遇到错误，该属性不存在。我通过运行

确认了feed解析器具有命名空间

print feed['namespaces']

给了我

{'': u'http://www.w3.org/2005/Atom', u'gd': u'http://schemas.google.com/g/2005', u'thr': u'http://purl.org/syndication/thread/1.0', u'openSearch': u'http://a9.com/-/spec/opensearchrss/1.0/'}