Question

我有这个简单的代码从我的mysql数据库中收集数据：

$get = mysql_query("SELECT * FROM table ORDER BY dato ASC") or die(mysql_error());
if(mysql_num_rows($get)) {
while($show = mysql_fetch_array($get)) {

}
} else {
echo "No results";
}

但是这个列表现在超过了200个项目，我想在日期上对它们进行排序，例如我已经做过了。

26/08-2015
1. line
2. line
3. line
4. line

27/08-2015
5. line
6. line
7. line

而不是

1. line
2. line
3. line
4. line
5. line
6. line
7. line

我现在得到了

我排序的日期是mktime日期。

$dato = mktime(0, 0, 0, date('m'), date('d'), date('y'));

Answer 1

使用此

$currentDate = null;
$get = mysql_query("SELECT * FROM table ORDER BY dato ASC") or die(mysql_error());
if(mysql_num_rows($get)) {
while($show = mysql_fetch_array($get)) {
if($currentDate != $show['dato'])
     echo "<BR><BR>";
$currentDate = $show['dato'];
}
} else {
echo "No results";
}

Answer 2

使用此，

$get = mysql_query("SELECT DISTINCT(DATE(`date`)) as dt, t.* FROM table t ORDER BY 1") or die(mysql_error());
if(mysql_num_rows($get)) {
    $prevDT = "";
    while($show = mysql_fetch_array($get)) {
        if (strlen($prevDT) < 0 || strcmp($prevDT, $show['dt']) != 0){
            echo("<br />");
            echo($show['dt']."<br />");
            $prevDT = $show['dt'];
        }
        echo($show['field']."<br />");
    }
} else {
    echo "No results";
}

在特定日期之后排序php

2 个答案: