Question

您对如何在特定日期之后指定一周的日期有任何想法吗？我正在使用一个日期选择器来获取我的开始时间，以及我如何将其转换为日期。

$formatdate = str_replace("(/\)", "-", $startdate);
$time2 = strtotime( $formatdate );
$date = date('Y-m-d', $time);

我需要知道开始日期1周后的日期才能在我的mysql查询中使用它。就像这样。

SELECT * FROM `table` WHERE `date` BETWEEN '$stardate' AND '$enddate'

谢谢你们！任何帮助都将得到充分的赞赏。

Answer 1

试试这个

<?php
$currentDate=date("Y-m-d");
$dateOneWeekAdded = strtotime(date("Y-m-d", strtotime($currentDate)) . " +1 week");
echo date("Y-m-d",$dateOneWeekAdded);
?>

修改：对于特定日期，您可以将上述代码重写为

<?php
$currentDate="08/14/2012";
$dateOneWeekAdded = strtotime(date("Y-m-d", strtotime($currentDate)) . " +1 week");
echo date("Y-m-d",$dateOneWeekAdded);
?>

Answer 2

$formatdate = str_replace("(/\)", "-", $startdate);
$start = new DateTime( $formatdate );
$startdate = $start->format("Y-m-d H:i:s");
$next_week = clone $start;
$next_week->add(new DateInterval("P1W"));
$enddate = $next_week->format("Y-m-d H:i:s");
$sql = "SELECT * FROM `table` WHERE `date` BETWEEN '$stardate' AND '$enddate'";

Answer 3

减少代码行数：

$end = new DateTime("today +1 week"); 
print $end->format('Y-m-d');

对于特定日期：

$start = "2012-10-24";
$end = new DateTime("$start +1 week"); 
print $end->format('Y-m-d');

Answer 4

或者你也可以使用MySQL：

SELECT * FROM table WHERE date BETWEEN '$stardate' AND DATE_ADD('$stardate', INTERVAL 7 DAY)

在php的特定日期后一周

4 个答案: