有谁可以告诉我为什么这种方法不起作用?
String strQuery = "Insert Into cust_subs (CustomerId,SubscriptionId) Values (?,?)";
PreparedStatement objPreparedStatement = Utils.getPreparedStatement(objConnection, strQuery);
objPreparedStatement.setInt(2, currentSubscriptions.get(0) );
其中currentSubscriptions
是:
List<Integer> currentSubscriptions;
即使它是整数列表,我也会收到此错误: -
SEVERE:java.lang.ClassCastException:java.lang.String无法强制转换为java.lang.Integer
假设连接对象已存在。而且我非常确定currentSubscriptions
不是null,否则我就不会有这个错误。如果不是像List
那样使用硬编码:
objPreparedStatement.setInt(2,1);
有效。我甚至使用System.out.println打印了List
的值,它非常好。它们只是整数。不知道为什么把它们视为字符串。我甚至在列表的项目上尝试了Integer.parseInt
。它仍然给我同样的错误。这是我遇到的最有趣的错误之一。
提前致谢:)
编辑: -
至少这应该有效。但即使这样也行不通: -
int intSubscriptionId = Integer.parseInt( currentSubscriptions.get(0).toString());
objPreparedStatement.setInt(2, intSubscriptionId );
编辑2:
发布完整代码: -
package beans;
import entities.Customer;
import entities.Subscription;
import java.io.IOException;
import java.io.Serializable;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Savepoint;
import java.util.ArrayList;
import java.util.List;
import javax.faces.bean.ManagedBean;
import javax.faces.bean.ViewScoped;
import javax.faces.context.FacesContext;
import javax.servlet.http.HttpServletRequest;
import misc.Utils;
@ManagedBean
@ViewScoped
public class AddSubscriptionBean implements Serializable {
private Customer customer;
private List<Integer> currentSubscriptions;
private List<Subscription> subscriptionList;
public List<Subscription> getSubscriptionList() {
return subscriptionList;
}
public void setSubscriptionList(List<Subscription> subscriptionList) {
this.subscriptionList = subscriptionList;
}
public List<Integer> getCurrentSubscriptions() {
return currentSubscriptions;
}
public void setCurrentSubscriptions(List<Integer> currentSubscriptions) {
this.currentSubscriptions = currentSubscriptions;
}
public Customer getCustomer() {
return customer;
}
public void setCustomer(Customer customer) {
this.customer = customer;
}
/** Creates a new instance of AddSubscriptionBean */
public AddSubscriptionBean() throws IOException, SQLException {
Connection objConnection = null;
try {
HttpServletRequest objHttpServletRequest = (HttpServletRequest) FacesContext.getCurrentInstance().getExternalContext().getRequest();
int intCustomerId = Integer.parseInt(objHttpServletRequest.getParameter("cid"));
String strQuery = "Select * from customer Where CustomerID = " + intCustomerId;
ResultSet objResultSet = Utils.executeResultSet(objConnection, strQuery);
if (objResultSet.next()) {
String strFirstName = objResultSet.getString("FirstName");
String strLastName = objResultSet.getString("LastName");
customer = new Customer(intCustomerId, strFirstName, strLastName);
}
currentSubscriptions = new ArrayList<Integer>();
for (Subscription objSubscription : customer.getSubscriptionList()) {
currentSubscriptions.add(objSubscription.getSubscriptionId());
}
subscriptionList = new ArrayList<Subscription>();
strQuery = "Select * from subscription";
objResultSet = Utils.executeResultSet(objConnection, strQuery);
while (objResultSet.next()) {
int intSubscriptionId = objResultSet.getInt("SubscriptionId");
String strSubsriptionTitle = objResultSet.getString("Title");
String strSubsriptionType = objResultSet.getString("Type");
Subscription objSubscription = new Subscription(intSubscriptionId, strSubsriptionTitle, strSubsriptionType);
subscriptionList.add(objSubscription);
}
} catch (Exception ex) {
ex.printStackTrace();
FacesContext.getCurrentInstance().getExternalContext().redirect("index.jsf");
} finally {
if (objConnection != null) {
objConnection.close();
}
}
}
public void save() throws SQLException {
Connection objConnection = null;
Savepoint objSavepoint = null;
try {
objConnection = Utils.getConnection();
objConnection.setAutoCommit(false);
objSavepoint = objConnection.setSavepoint();
String strQuery = "Delete From cust_subs Where CustomerId = " + customer.getCustomerId();
if (!Utils.executeQuery(objConnection, strQuery)) {
throw new Exception();
}
strQuery = "Insert Into cust_subs (CustomerId,SubscriptionId) Values (?,?)";
int intCustomerId = customer.getCustomerId();
PreparedStatement objPreparedStatement = Utils.getPreparedStatement(objConnection, strQuery);
for (int intIndex = 0; intIndex < currentSubscriptions.size(); intIndex++) {
objPreparedStatement.setInt(1, intCustomerId);
int intSubscriptionId = Integer.parseInt( currentSubscriptions.get(0).toString());
objPreparedStatement.setInt(2, intSubscriptionId );
objPreparedStatement.addBatch();
}
objPreparedStatement.executeBatch();
objConnection.commit();
} catch (Exception ex) {
ex.printStackTrace();
if (objConnection != null) {
objConnection.rollback(objSavepoint);
}
} finally {
if (objConnection != null) {
objConnection.close();
}
}
}
}
这是我的JSF页面: -
<?xml version='1.0' encoding='UTF-8' ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
xmlns:h="http://java.sun.com/jsf/html"
xmlns:f="http://java.sun.com/jsf/core"
xmlns:msc="http://mscit/jsf">
<h:head>
<title>Facelet Title</title>
</h:head>
<h:body>
<center>
<h:form>
<h1>Add Subscription</h1>
<b> Customer Name :</b> <h:outputText value="#{addSubscriptionBean.customer.firstName} #{addSubscriptionBean.customer.lastName}"/>
<h:selectManyCheckbox value="#{addSubscriptionBean.currentSubscriptions}">
<f:selectItems value="#{addSubscriptionBean.subscriptionList}" var="row" itemLabel="#{row.title}" itemValue="#{row.subscriptionId}" />
</h:selectManyCheckbox>
<h:commandButton value="Save" actionListener="#{addSubscriptionBean.save}"/>
</h:form>
</center>
</h:body>
</html>
请查看JSF的h:selectManyCheckbox。 JSF在内部将我检查过的所有复选框传递给我的列表。我认为JSF正在将我的整数列表转换为字符串。
答案 0 :(得分:6)
您需要指示h:selectManyCheckbox
将Integer
指定为转换器,将值转换为javax.faces.Integer
。 EL中的通用类型是未知的,它默认将参数视为String
。
<h:selectManyCheckbox converter="javax.faces.Integer">
不需要使用List<String>
代替,这只会导致bean中出现更多弱类型的混乱。
答案 1 :(得分:3)
如果使用不安全的操作,可以将字符串放入List<Integer>
:
List<Integer> intList = new ArrayList<Integer>();
List list = intList;
list.add("1");
intList
和list
保持对同一列表的引用,该列表现在包含一个字符串。如您所见,在尝试从ClassCastException
中提取元素时,您会获得intList
。
Java泛型使用隐藏转换工作,您可以打败类型检查。要测试它,请分配给List
,然后打印每个元素的类:
List currentSubscriptionsUnsafe = currentSubscriptions;
for(Object o : currentSubscriptionsUnsafe)
{
System.out.println(o.getClass());
}
编辑:我不熟悉JSF,但我认为您的猜测是正确的。一种解决方案是让currentSubscriptions
到处都是List<String>
(JSF似乎期待)。然后,get(0)
将返回String
,您可以将其解析为Integer
。可能有一个更干净的方法,但这应该有效。