Question

示例数据：

ID Name   Role
1  Jack   Manager
2  John   Manager
3  James  Employee
4  Helen  Employee
5  Tony   Manager
6  Louise Employee

我怎么能回来：

Name               Role
Jack, John, Louise Manager
James              Employee
Helen              Employee
Louise             Employee

我想我只需要在特定组中使用带有XML的STUFF。请指教。

然后我需要进一步操纵：

Name   ListOfManagers     Role
NULL   Jack, John, Louise Manager
James  NULL               Employee
Helen  NULL               Employee
Louise NULL               Employee

谢谢。

Answer 1

您可以使用XML PATH类Role特定过滤器。

<强> SQL Fiddle

示例数据

CREATE TABLE Employee
    ([ID] int, [Name] varchar(6), [Role] varchar(8));

INSERT INTO Employee
    ([ID], [Name], [Role])
VALUES
    (1, 'Jack', 'Manager'),
    (2, 'John', 'Manager'),
    (3, 'James', 'Employee'),
    (4, 'Helen', 'Employee'),
    (5, 'Tony', 'Manager'),
    (6, 'Louise', 'Employee');

<强>查询

SELECT DISTINCT STUFF((
SELECT ',' + Name 
FROM Employee E2
WHERE (E1.Role = 'Manager' OR E1.ID = E2.ID)
ORDER BY ID ASC
FOR XML PATH('')
),1,1,'') as Name,Role
FROM Employee E1

<强>输出

Name    Role
Helen   Employee
Jack,John,James,Helen,Tony,Louise   Manager
James   Employee
Louise  Employee

您甚至可以选择UNION 2个不同的一组用于管理员GROUP BY和一个用于员工，并且仅在管理员查询中使用XML路径。

修改

根据更新后的问题，您可以像这样使用UNION ALL ..

<强> SQL Fiddle

<强>查询

SELECT NULL as Name, STUFF(( SELECT ',' + Name FROM Employee E2 WHERE E2.Role = E1.Role ORDER BY ID ASC FOR XML PATH('') ),1,1,'') as ListofManagers, Role FROM Employee E1 WHERE Role = 'Manager' GROUP BY Role UNION ALL SELECT Name,NULL,Role FROM Employee WHERE Role = 'Employee'

<强>输出

| Name | ListofManagers | Role | |--------|----------------|----------| | (null) | Jack,John,Tony | Manager | | James | (null) | Employee | | Helen | (null) | Employee | | Louise | (null) | Employee |

T-SQL - 仅限某些组的CSV

1 个答案: