Question

import random
numbers = []
wheel1 = 0
wheel2 = 0
wheel3 = 0
winnings = int(0)
balance = int(50)

def generator(balance):

    number1 = random.random()
    number2 = random.random()
    number3 = random.random()

    if number1 < 0.05:
        wheel1 = "Cherry"
    elif number1 < 0.15:
        wheel1 = "Diamond"
    elif number1 < 0.30:
        wheel1 = "Hearts"    
    elif number1 < 0.65:
        wheel1 = "Spade"    
    elif number1 < 1:
        wheel1 = "Monkey"  

    if number2 < 0.05:
        wheel2 = "Cherry"
    elif number2 < 0.15:
        wheel2 = "Diamond"
    elif number2 < 0.30:
        wheel2 = "Hearts"    
    elif number2 < 0.65:
        wheel2 = "Spade"    
    elif number2 < 1:
        wheel2 = "Monkey"

    if number3 < 0.05:
        wheel3 = "Cherry"
    elif number3 < 0.15:
        wheel3 = "Diamond"
    elif number3 < 0.30:
        wheel3 = "Hearts"    
    elif number3 < 0.65:
        wheel3 = "Spade"    
    elif number3 < 1:
        wheel3 = "Monkey"

    return wheel1
    return wheel2
    return wheel3

def win(generator,balance):

    generator(balance)

    if wheel1 =="Monkey"and wheel2 == "Monkey"and wheel3 == "Monkey":
        print "JACKPOT!"
        winnings = int(50)
        balance + winnings
        print 'JACKPOT!'

    else:
        print 'noice'
        winnings = int(10)
        balance + winnings
        print 'noice'

    return balance


print "Welcome to the International Slot Machine"
print ""
print "Balance: $",balance
print ''
spinyn = (raw_input("Would you like to spin? $5 per spin. Enter y or n:\n"))
while True:
    if spinyn == "y":
        break
    elif spinyn == "n":
        print "Final Balance: $",balance
        print "Thank you for using the International Slot Machine"
        raise SystemExit
    else:
        spinyn = raw_input('\033[31mPlease enter only y or n.\033[0m\n')    
spin = (raw_input("Press enter to spin for $5:\n"))
while True:
    if spin == '':
        balance = balance - 5
        if balance <= 0:
            print ""
            print "Final Balance: $",balance
            print "You have run out of money, the game has now ended."
            raise SystemExit
        print ""
        print "\033[34mResult:\033[0m"
        print "\033[34m-------\033[0m"
        balance = generator(balance)
        print ""
        print win(generator,balance)
        print "New balance:$",balance
        print ""
        spinagain = (raw_input("Would you like to spin again? Press enter to spin again, type anything to exit.\n"))
        while True:
            if spinagain == "":
                break
            else:
                print "Final Balance: $",balance
                print "Thank you for using the International Slot Machine"
                raise SystemExit
    else:
        spin = (raw_input("Please press enter to spin.\n"))

我很欣赏有关选择随机符号的方法的任何建议，但请保留，因为我只有一个问题。我的问题是：在win功能中，如何识别3轮输出。我已经完成了我认为可行的工作，但它没有，即使我落在3只猴子身上。

欢迎任何其他建议。但请记住，这是最重要的。

非常感谢你。

Answer 1

你在这里遇到的问题是你的范围概念需要一些帮助。

This answer是一个非常好的开始。

举一个简短的代码示例，让我们这样做：

def generator(balance):
    wheel_1 = 'Monkey'
    wheel_2 = 'Diamond'
    wheel_3 = 'Heart'

    return wheel_1, wheel_2, wheel_3


def win(generator):
    print wheel_1, wheel_2, wheel_3

win(generator)

您在此处获得的是NameError，因为wheel_1（和2＆amp; 3）实际上并不存在于win功能中。它们仅存在于生成器函数中。所以你需要做的是从生成器函数中获取的值，并将它们放在“赢得”的地方。可以看到。实际上，您可以非常轻松地执行此操作，因为我们已经从generator函数返回值：

# Note: generator was removed as a parameter. # We don't need it here, because if Python # can't find the name `generator` it will look # in the enclosing scope and find the function # `generator` there. def win(): # What we want to do is *call* `generator` and # assign the results to some variables that *are* # in `win`'s scope wheel_1, wheel_2, wheel_3 = generator() print wheel_1, wheel_2, wheel_3

正如您所提到的，您当然可以改进当前代码中的某些内容。您已经注意到generator功能中的代码看起来几乎完全相同。当你看到代码并且你得到那种感觉时，这就是所谓的代码气味＆＃34;。当你的（有意识的）头脑看到它所知道的某些代码可以得到改善时会发生什么。在这种特殊情况下，有一个原则叫做 DRY - D R 重新 Y 我们自己。

您可以使用以下内容替换现有代码：

def spin_one(): number = random.random() if number < 0.05: result = 'Cherry' elif number < 0.15: result = 'Diamond' elif number < 0.30: result = 'Hearts' elif number < 0.65: result = 'Spade' else: result = 'Monkey' return result def generator(): return spin_one(), spin_one(), spin_one()

我甚至可能会完全删除生成器调用，只需执行此操作：

if all((spin_one() == 'Monkey' for _ in xrange(3))):

您可以阅读all上的文档。

但是，如果你想获得的不仅仅是赢得很多并赢得一点点，那么你需要保持这些价值观：

wheels = [spin_one() for _ in xrange(3)]

然后你可以这样做：

if all(wheel == 'Monkey' for wheel in wheels): # Alternatively, wheels.count('Monkey') == 3 print 'Jackpot' elif wheels.count('Hearts') == 2: print 'Win' elif all(wheel == 'Lemon' for wheel in wheels): print 'You lose'

您可能想要添加任何其他类型的获胜。

<强>提示

我不认为这比你当前的快速方法更好或更差，但我过去常常在我的C ++课程中使用它。

def prompt(): choice = raw_input('(Y)es or (N)o: ').lower() if choice == 'y': return True elif choice == 'n': return False else: print '**ERROR** Please input "y" or "n"' return prompt()

这是一个很好的，简单的方法来处理递归：）

Python 2.7 Slot Machine if语句问题

1 个答案: