Question

        import random
        balance = 50

        def generator():
            slot = 0
            count = 0
            gen = random.random()
            while count < 3:
                count = count + 1
                if gen <= 0.01:
                        slot = 'Cherry'
                elif gen <= 0.06:
                        slot = 'Diamond'
                elif gen <= 0.16:
                        slot = 'Heart'
                elif gen <= 0.36:
                        slot = 'Spade'
                elif gen <= 0.66:
                        slot = 'Club'
                elif gen <= 1:
                        slot = 'Monkey'
                else:
                    break

            return slot


        def win(generator):
            if generator() == 'Monkey' and generator() == 'Monkey' and generator() == 'Monkey':
                balance = balance + 2122

        print "Welcome to the International Slot Machine"
        print ""
        print "Balance: $",balance
        print ''
        spinyn = (raw_input("Would you like to spin? $5 per spin. Enter y or n:\n"))
        while True:
            if spinyn == "y":
                break
            elif spinyn == "n":
                print "Final Balance: $",balance
                print "Thank you for using the International Slot Machine"
                raise SystemExit
            else:
                spinyn = raw_input('\033[31mPlease enter only y or n.\033[0m\n')

        spin = (raw_input("Press enter to spin for $5:\n"))
        while True:
            if spin == '':
                balance = balance - 5
                if balance <= 0:
                    print ""
                    print "Final Balance: $",balance
                    print "You have run out of money, the game has now ended."
                    raise SystemExit
                print ""
                print "\033[34mResult:\033[0m"
                print "\033[34m-------\033[0m"
                print generator()
                print generator()
                print generator()
                print ""
                print "New balance:$",balance
                print ""
                spinagain = (raw_input("Would you like to spin again? Press enter to spin again, type anything to exit.\n"))
                while True:
                    if spinagain == "":
                        break
                    else:
                        print "Final Balance: $",balance
                        print "Thank you for using the International Slot Machine"
                        raise SystemExit
            else:
                spin = (raw_input("Please press enter to spin.\n"))

我正在尝试制作一台非常基本的老虎机。

我的问题是：如何使生成器功能重复3次并返回3个输出，然后如何让它识别某些组合？

这是否可行，与我目前的格式保持一致？

另外，我如何将数组合并到我的代码中？感谢

Answer 1

生成三个值后，生成器返回三个值的列表或元组，使用random.choice()而不是random.random()也会更容易。 random.choice()随机选择一个元素列表值/迭代，所有元素的概率相等。示例 -

def generator():
    ret = []
    for _ in range(3):
        ret.append(random.choice(['Cherry','Diamond','Heart','Spade','Club','Monkey']))
    return tuple(ret)

如果你想为不同的元素设置不同的概率，你可以保留当前的方法，只需循环三次，然后像上面那样追加ret并从中返回ret。

然后在你的win函数中，保留一个字典，使得键是组合的元组，值是用户获胜的数量，然后你可以简单地使用默认值为0的.get()来获取用户赢了多少。不要传递generator作为参数。示例 -

def win():
    roll = generator()
    d = {('Monkey','Monkey','Monkey'):21222,...}
    return d.get(roll,0)

然后在您的主循环中，调用此win()函数滚动并查看用户赢得了多少。

Answer 2

使用范围功能选择3次并将其存储在列表中。

import random

choices_list=[]
for ctr in range(3):
    gen = random.choice(['Cherry', 'Diamond', 'Heart',
                     'Spade', 'Club', 'Monkey'])
    choices_list.append(gen)

print choices_list

Python老虎机问题

2 个答案: