无论user_hand中有哪些卡，我的返回值总是打印出20个。有什么理由为什么？
suits = ["Heart", "Diamond", "Spade", "Club"]
ranks = ['A', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K']
deck = [(suit, rank) for rank in ranks for suit in suits]
random.shuffle(deck,random.random)
user_hand = []
dealer_hand = []
user_hand.append(deck.pop())
dealer_hand.append(deck.pop())
user_hand.append(deck.pop())
dealer_hand.append(deck.pop())
def handtotal (hand):
total = 0
for rank in hand:
if rank == "J" or "Q" or "K":
total += 10
elif rank == 'A' and total < 11:
total += 11
elif rank == 'A' and total >= 11:
total += 1
elif rank == '2':
total += 2
elif rank == '3':
total += 3
elif rank == '4':
total += 4
elif rank == '5':
total += 5
elif rank == '6':
total += 6
elif rank == '7':
total += 7
elif rank == '8':
total += 8
elif rank == '9':
total += 9
return total
print ("Your current hand is {}".format(user_hand))
print ("This provides you with a total of:")
print (handtotal(user_hand))
答案 0 :(得分：1)
你的一个问题是这一行：
if rank == "J" or "Q" or "K"
就目前而言，这将始终评估为真（嗯，技术上＆＃34; Q＆＃34;）。您应该将rank与所有变量进行比较：
if rank == "J" or rank == "Q" or rank == "K"
或更多Pythonic方式：
if rank in ["J", "Q", "K"]
此外，您已将user_hand传递给handtotal()。由于user_hand的每个元素都是元组，因此您需要与rank[1]的每个元素（例如user_hand）的第二个元素进行比较。
答案 1 :(得分：0)
你应该改变这个：
if rank == "J" or "Q" or "K":
对此：
if rank in ["J", "Q", "K"]:
有关详细信息，请参阅operator precedence。
答案 2 :(得分：-1)
正如人们所说，你的第一个如果不好。
另外，当我试图运行你的代码时，我也注意到你没有比较排名，而是'卡'（整个对）
您的代码如下：
import random
suits = ["Heart", "Diamond", "Spade", "Club"]
ranks = ['A', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K']
deck = [(suit, rank) for rank in ranks for suit in suits]
random.shuffle(deck,random.random)
user_hand = []
dealer_hand = []
user_hand.append(deck.pop())
dealer_hand.append(deck.pop())
user_hand.append(deck.pop())
dealer_hand.append(deck.pop())
def handtotal (hand):
total = 0
for rank in hand:
if rank[1] == "J" or rank[1] == "Q" or rank[1] == "K":
total += 10
elif rank[1] == 'A' and total < 11:
total += 11
elif rank[1] == 'A' and total >= 11:
total += 1
elif rank[1] == '2':
total += 2
elif rank[1] == '3':
total += 3
elif rank[1] == '4':
total += 4
elif rank[1] == '5':
total += 5
elif rank[1] == '6':
total += 6
elif rank[1] == '7':
total += 7
elif rank[1] == '8':
total += 8
elif rank[1] == '9':
total += 9
return total
print ("Your current hand is {}".format(user_hand))
print ("This provides you with a total of:")
print (handtotal(user_hand))
答案 3 :(得分：-1)
此代码适用于此处：
import random
suits = ["Heart", "Diamond", "Spade", "Club"]
ranks = ['A', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K']
deck = [(suit, rank) for rank in ranks for suit in suits]
random.shuffle(deck,random.random)
user_hand = []
dealer_hand = []
user_hand.append(deck.pop())
dealer_hand.append(deck.pop())
user_hand.append(deck.pop())
dealer_hand.append(deck.pop())
def handtotal (hand):
total = 0
for rank in hand:
rank = rank[1]
if rank in ["J", "Q","K"]:
total += 10
elif rank == 'A' and total < 11:
total += 11
elif rank == 'A' and total >= 11:
total += 1
elif rank == '2':
total += 2
elif rank == '3':
total += 3
elif rank == '4':
total += 4
elif rank == '5':
total += 5
elif rank == '6':
total += 6
elif rank == '7':
total += 7
elif rank == '8':
total += 8
elif rank == '9':
total += 9
return total
print ("Your current hand is {}".format(user_hand))
print ("This provides you with a total of:")
print (handtotal(user_hand))
答案 4 :(得分：-2)
我认为问题在于：
如果排名==＆＃34; J＆＃34;或＆＃34; Q＆＃34;或者＆＃34; K＆＃34;：
我知道你可以用python做很多奇怪的事情，但我很确定这句话应该是
如果排名==＆＃34; J＆＃34;或排名==＆＃34; Q＆＃34;或排名==＆＃34; K＆＃34; ...