解决
好吧,当我尝试删除我的类指针时,似乎我收到了分段错误。我尝试了很多东西,但还没有让它发挥作用。无论如何,这是我的 main.cpp :(当我删除'm'时发生这种分段错误)
/*
* Copyright(c)Fellixombc 2010
*
* TextToSqlRs is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* TextToSqlRs is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with TextToSqlRs. If not, see <http://www.gnu.org/licenses/>.
*/
#include <ctime>
#include <iostream>
#include <unistd.h>
#include <string>
#include "eMysql.h"
#include "manage.h"
using namespace std;
int main() {
time_t start, stop;
double TIME;
string host, user, password, database;
string path;
bool run = true;
int runtime;
int MAX;
int max;
cout << "Please enter the required information." << endl << "Absolute path to character folder: ";
cin >> path;
cout << "MySql Database Host: ";
cin >> host;
cout << "MySql Username: ";
cin >> user;
cout << "MySql Password: ";
cin >> password;
cout << "Database name: ";
cin >> database;
start = clock();
eMysql* m = new eMysql;
Manage* manage = new Manage;
m->connect(host.c_str(), user.c_str(), password.c_str(), database.c_str());
manage->ReadDir(path);
manage->TextToSql(m);
delete manage;
delete m;
stop = clock();
TIME = ((double)stop - (double)start)/CLOCKS_PER_SEC;
cout << "Finished in " << TIME << " seconds" << endl; }
eMysql deconstructor:
eMysql::~eMysql() {
mysql_free_result(result);
mysql_close(&mysql);
if(lengths) delete lengths;
if(result) delete result; }
mysql / result header:
#ifndef _MYSQL_H
#define _MYSQL_H
#include <iostream>
#include <stdlib.h>
#include <string.h>
#include <fstream>
#include <mysql/mysql.h>
#include <string>
using namespace std;
class eMysql {
public:
eMysql();
int connect(const string, const string, const string, const string);
int query(string query);
int strip(string&);
int rows();
virtual ~eMysql();
private:
MYSQL mysql;
MYSQL_RES *result;
MYSQL_ROW row;
unsigned int i;
};
#endif /* _MYSQL_H */
mysql初始化程序
eMysql::eMysql() {
mysql_init(&mysql);
}
结果初始化程序
int eMysql::query(string query) {
if(mysql_query(&mysql, query.c_str())) {
cout << "Failed to run query: " << mysql_error(&mysql) << endl;
exit(1);
}
result = mysql_store_result(&mysql);
query.erase();
return 1;
}
答案 0 :(得分:1)
我没有看到任何初始化lengths
或result
的代码,因此您可能正在删除野生指针。
答案 1 :(得分:1)
由于您从未致电query
,因此您正在使用无效的result
指针进行操作。在eMysql
构造函数中,将result
初始化为NULL
:
eMysql::eMysql() : result(NULL) {
// ...
}
然后,在析构函数中:
eMysql::~eMysql() {
if (result) mysql_free_result(result);
mysql_close(&mysql);
}
析构函数中有一件事看起来不对:
eMysql::~eMysql() {
// You use "result" here, but later check if it's not NULL.
// You should only free if it's not null.
mysql_free_result(result);
mysql_close(&mysql);
if(lengths) delete lengths;
// Are you sure you need to delete this? Isn't that what the
// mysql_free_result is for? This will still be a non-NULL ptr
// that has already been free'd. This might be a double-delete
// which would likely manifest as a segmentation fault.
if(result) delete result;
}
但可能还有其他问题。
TextToSQL
取得m
的所有权吗?result
和mysql
是否在~eMysql
?lengths
被分配为数组吗?使用delete [] lengths;
以下是一些用于调试这些类型问题的方法(在Linux上):