指针上的分段错误

Question

#include<stdio.h>
#include<malloc.h>

int main(){
    int count,i,j;
    int* val;
    scanf("%d",count);
    val = (int*)malloc(sizeof(int)*count);
    if(NULL == val){
        printf("\n memory is NULl \n");
    }
    for(i=0;i<count;i++){
        scanf("%d",val[i]);
    }
    for(i=0;i<count;i++){
        for(j=1;j<=val[i];j++){
            if((j%3) == 0){
                printf("Fizz\n");
            }
            else if((j%5) == 0){
                printf("Buzz\n");
            }
            else{
                printf("%d\n",j);
            }
        }
    }
    return 0;
}

O / P：

2
Segmentation fault

Answer 1

scanf("%d",count);

没有＆amp;在scanf中。它应该是

scanf("%d",&count);

Answer 2

将scanf("%d",count)更改为scanf("%d",&count)。

同时更改

for(i=0;i<count;i++){
    scanf("%d",val[i]);

到

for(i = 0; i < count; i++){
    scanf("%d", &val[i]);

Answer 3

替换

  

“的scanf（” ％d “计数）;” “scanf（”％d“，＆amp; count）;”

和

  

“的scanf（” ％d “VAL [I]）;” “scanf（”％d“，＆amp; val [i]）;”