我有一个包含18个不同键的字典,每个键都有3个值(xPower
,xPP
和xAccuracy
)每个变量都包含一个int。我如何从某个键访问一个值?例如,我想取出ScratchPower
(40)的值以供其他地方使用。搜索了半个多小时后,我发现的最多的是访问密钥中的所有值:
print defMoves["Scratch"]
这是我的字典:
defMoves = {
"Scratch": [ScratchPower, ScratchPP, ScratchAccuracy],
"Air Slash": [Air_SlashPower, Air_SlashPP, Air_SlashAccuracy],
"Flare Blitz": [Flare_BlitzPower, Flare_BlitzPP, Flare_BlitzAccuracy],
"Growl": [GrowlPower, GrowlPP, GrowlAccuracy],
"Heat Wave": [Heat_WavePower, Heat_WavePP, Heat_WaveAccuracy],
"Ember": [EmberPower, EmberPP, EmberAccuracy],
"Shadow Claw": [Shadow_ClawPower, Shadow_ClawPP, Shadow_ClawAccuracy],
"Smokescreen": [SmokescreenPower, SmokescreenPP, SmokescreenAccuracy],
"Dragon Claw": [Dragon_ClawPower, Dragon_ClawPP, Dragon_ClawAccuracy],
"Dragon Rage": [Dragon_RagePower, Dragon_RagePP, Dragon_RageAccuracy],
"Scary Face": [Scary_FacePower, Scary_FacePP, Scary_FaceAccuracy],
"Fire Fang": [Fire_FangPower, Fire_FangPP, Fire_FangAccuracy],
"Flame Burst": [Flame_BurstPower, Flame_BurstPP, Flame_BurstAccuracy],
"Wing Attack": [Wing_AttackPower, Wing_AttackPP, Wing_AttackAccuracy],
"Slash": [SlashPower, SlashPP, SlashAccuracy],
"Flamethrower": [FlamethrowerPower, FlamethrowerPP, FlamethrowerAccuracy],
"Fire Spin": [Fire_SpinPower, Fire_SpinPP, Fire_SpinAccuracy],
"Inferno": [InfernoPower, InfernoPP, InfernoAccuracy],
}
由于
答案 0 :(得分:1)
defMoves["Scratch"]
返回一个列表,所以只需索引就像任何列表一样:
defMoves["Scratch"][0] # first subelement -> ScratchPower
defMoves["Scratch"][1] # second subelement -> ScratchPP
defMoves["Scratch"][2] # third subelement -> ScratchAccuracy
......
答案 1 :(得分:0)
defMoves [“Scratch”]让你回到这个值,在这种情况下是一个列表,与该键相关联。要从该列表中获取特定项,您需要使用数字索引。因此,例如,要获得ScratchPower,您将使用defMoves [“Scratch”] [0]。
但是,这似乎很难跟踪,所以你可能想在每个词典中使用另一个词典。那看起来像是
{"Scratch" : {"Power":40... }... }