Question

当我取消注释下面main（）中的行时，Visual Studio 2015不会编译（否则代码会编译）。

#include <iostream>
#include <type_traits>

template <typename Output, std::size_t... Input> struct RemoveLastHelper;

template <template <std::size_t...> class Z, std::size_t... Accumulated, std::size_t First, std::size_t... Rest>
struct RemoveLastHelper<Z<Accumulated...>, First, Rest...> :
    RemoveLastHelper<Z<Accumulated..., First>, Rest...> {};

template <template <std::size_t...> class Z, std::size_t... Accumulated, std::size_t Last>
struct RemoveLastHelper<Z<Accumulated...>, Last> {
    using type = Z<Accumulated...>;
};

template <template <std::size_t...> class Z, std::size_t... Is>
using RemoveLast = RemoveLastHelper<Z<>, Is...>;

struct Base {
    virtual ~Base() = default;
    virtual void foo() const = 0;
};

template <std::size_t... Is> struct Derived;

template <std::size_t R>
struct Derived<R> : public Base {
    virtual void foo() const override {}
};

// For example, Derived<R,D1,D2,D3> inherits from Derived<R,D1,D2>, which inherits from
// Derived<R,D1>, which inherits from Derived<R>, which inherits from Base (by the above).
template <std::size_t R, std::size_t... Is>
struct Derived<R, Is...> : public RemoveLast<Derived, R, Is...>::type {
    virtual void foo() const override {RemoveLast<Derived, R, Is...>::type::foo();}
};

int main() {
//  Derived<0,2,1> r;  // This line won't compile.
}

它给出了错误：

'Derived<0,2>': invalid template argument for template parameter 'Z', expected a class template
'RemoveLast': left of '::' must be a class/struct/union
'type': is not a class or namespace name

那么这里有什么问题？ GCC 5.1编译它，但我想知道这是否只是一个侥幸。语法virtual void foo() const override {RemoveLast<Derived, R, Is...>::type::foo();}合法吗？如果没有，我该如何实现它（我只想让它调用它的基类＆＃39; foo（））。如果它是合法的，我该如何重写它以便Visual Studio接受它（我需要它在Visual Studio上工作）？

Answer 1

这是一个简单的解决方法。将Derived替换为Derived::template Derived。

template <std::size_t R, std::size_t... Is>
struct Derived<R, Is...> : public RemoveLast<Derived, R, Is...>::type {
    virtual void foo() const override {RemoveLast<Derived::template Derived, R, Is...>::type::foo();}
};

::Derived也有效。这似乎是Clang和Visual Studio中关于注入类名称的错误。

这种语法合法吗？

1 个答案: