我正在尝试以不同的方式学习PHP以提高我的技能。这就是问题。有没有办法找出给定的树是否是BST (二叉搜索树)或不在 PHP 。我尝试使用C语言。任何人都可以帮助我使用PHP吗? 这是我用C语言编写的代码。
#include <stdio.h>
#include <stdlib.h>
struct node
{
int data;
struct node* left;
struct node* right;
};
static struct node *prev = NULL;
/*Function to check whether the tree is BST or not*/
int is_bst(struct node* root)
{
if (root)
{
if (!is_bst(root->left)) //moves towards the leftmost child of the tree and checks for the BST
return 0;
if (prev != NULL && root->data <= prev->data)
return 0;
prev = root;
return is_bst(root->right); //moves the corresponding right child of the tree and checks for the BST
}
return 1;
}
struct node* newNode(int data)
{
struct node* node = (struct node*)malloc(sizeof(struct node));
node->data = data;
node->left = NULL;
node->right = NULL;
return(node);
}
int main()
{
struct node *root = newNode(40);
root->left = newNode(20);
root->right = newNode(60);
root->left->left = newNode(10);
root->left->right = newNode(30);
root->right->right = newNode(80);
root->right->right->right = newNode(90);
if (is_bst(root))
printf("TREE 1 Is BST");
else
printf("TREE 1 Not a BST");
prev = NULL;
return 0;
}
答案 0 :(得分:0)
如果在PHP中声明/存在类定义和实例,则基本上可以运行相同的算法。
您的PHP代码目前是什么样的?