Question

有没有办法将嵌套的json转换为unnested对象我从Web服务中获得了嵌套的json

{
  name:"name"
  address:{addressName:"address",
           addressList:[{State:"state1",
                         City:"city1"},
                        {State:"state2",
                         City:"city2"}]
          }
}

我的域名就像

public class Person{
  private String name;
  private String addressName;
  private String addressState1;
  private String addressCity1;
  private String addressState2;
  private String addressCity2;
}

因为只有两个地址将由网络服务提供，所以我们不需要创建另一个域作为PersonAddress，是否有任何注释我可以使用功能 @JsonUnwrapped < / strong>，所以我把json投入了我的域名。

Answer 1

我猜你可以使用@JsonCreator和@JsonProperty构建一个Person的新实例，但我担心你还需要一个单独的PersonAddress和AddressDetails域类：

PersonAddress：

public class PersonAddress {
 private String addressName;
 private List<AddressDetails> addressList;
}

AddressDetails：

public class AddressDetails {
 private String state;
 private String city;
}

人：

public class Person {
  private String name;
  private String addressName;
  private String addressState1;
  private String addressCity1;
  private String addressState2;
  private String addressCity2;

  @JsonCreator
  public Person(@JsonProperty("name") String name, @JsonProperty("address") PersonAddress address) {
    this.addressName = address.addressName;
    this.addressState1 = address.addressList.get(0).getState();
    this.addressCity1 = address.addressList.get(0).getCity();
    this.addressState2 = address.addressList.get(1).getState();
    this.addressCity2 = address.addressList.get(1).getCity();
  }
}

请参阅以下代码示例：http://www.programcreek.com/java-api-examples/index.php?api=org.codehaus.jackson.annotate.JsonCreator

嵌套的json使用java转换unnested域

1 个答案: