Question

在C＃中，使用初始化语法我可以说：

string[] mystrings = {"one", "two", "three"};

是否可以使用相同的数组初始化语法来转换它：

string test = "This is a good sentance to split, it has at least one split word to split on.";
string[] mystrings = test.Split(new string[] { "split" }, StringSplitOptions.RemoveEmptyEntries);

这样的事情：

string test = "This is a good sentance to split, it has at least one split word to split on.";
string[] mystrings = test.Split({ "split" }, StringSplitOptions.RemoveEmptyEntries);

它似乎应该可行，但我无法做任何事情。

Answer 1

几乎就在那里：

string[] mystrings = test.Split(new[]{ "split" }, 
    StringSplitOptions.RemoveEmptyEntries);

Answer 2

您似乎需要新的string方法：

public static class StringExtensions {
  public static string[] Split(this string self, string separator, StringSplitOptions options) {
    return self.Split(new[] { separator }, options);
  }
}

像这样使用：

string[] mystrings = test.Split("split", StringSplitOptions.RemoveEmptyEntries);

现在，由你决定是否值得介绍它。

对于多个分隔符，您可以修复options参数（或将其放在前面，根据其他“重载”会感觉不自然）：

public static class StringExtensions {
  // maybe just call it Split
  public static string[] SplitAndRemoveEmptyEntries(this string self, params string[] separators) {
    return self.Split(separators, StringSplitOptions.RemoveEmptyEntries);
  }
}

用法：

string[] mystrings = test.SplitAndRemoveEmptyEntries("banana", "split");

Answer 3

您当然可以使用以下语法：

string test = "This is a good sentance to split, it has at least one split word to split on.";
string[] mystrings = test.Split(new[] { "split" }, StringSplitOptions.RemoveEmptyEntries);

但我不确定你是否可以进一步简化......

Answer 4

您可以添加扩展方法：

    public static String[] Split(this string myString, string mySeperator, StringSplitOptions options)
    {
        return myString.Split(new[] {mySeperator}, options);
    }

然后你可以这样做：

    string test = "This is a good sentance to split, it has at least one split word to split on.";
    string[] mystrings = test.Split("split", StringSplitOptions.RemoveEmptyEntries);

是否可以使用C＃初始化语法来传递参数？

4 个答案: