我试图将2个文本框的名称传递给方法,以便它编辑其中的文本。我尝试过在线查找示例,但只能找到尝试通过文本框传递文本的人。
我尝试通过在方法构造函数中声明文本框来传递它。
MethodName(string text, tb_1, tb_2);
private void MethodName(string str, TextBox tb_name, TextBox tb_allergen)
{
string ingredientName = "";
string ingredientAllergen = "";
//code to change strings//
tb_name.Text = ingredientName;
tb_allergen.Text = ingredientAllergen;
}
运行代码后,我希望将文本框文本更改为适当的值,而不是在调用中遇到有关文本框的错误。
“ mscorlib.dll中发生了'System.InvalidCastException'类型的未处理的异常
其他信息:无法将类型为'System.Windows.Forms.TextBox'的对象转换为类型为'System.IConvertible'“
如果对此有一个简单的解决方法,请对不起,但是请向我指出正确的方向。预先感谢。
真实代码
ingredientDBAccess ingredientDBA = new ingredientDBAccess(db);
populateBoxesWithIngredientResults( ingredientDBA.getIngredientsFromID(Convert.ToInt32(tb_viewIngredient1)), tb_viewIngredient1, tb_viewAllergen1);
private void populateBoxesWithIngredientResults(List<ingredient> ingredientList, TextBox tb_name, TextBox tb_allergen)
{
string ingredientName = "";
string ingredientAllergen = "";
foreach (ingredient ingredient in ingredientList)
{
string name = Convert.ToString(ingredient.IngredientName);
ingredientName = name;
string allergen = "N/A";
switch (ingredient.AllergenID)
{
case 0:
allergen = "N/A";
break;
case 1:
allergen = "Nut";
break;
case 2:
allergen = "Gluten";
break;
case 3:
allergen = "Dairy";
break;
case 4:
allergen = "Egg";
break;
}
ingredientAllergen = allergen;
}
tb_name.Text = ingredientName;
tb_allergen.Text = ingredientAllergen;
}
答案 0 :(得分:3)
是的,有可能:
void MyMethod(string str, TextBox txt)
{
txt.Text = str + " some text from the method itself";
}
您甚至可以返回TextBox:
TextBox MyFunc(string str)
{
TextBox txt = new TextBox();
txt.Text = str;
return txt;
}
您正在尝试将TextBox转换为Int32:
Convert.ToInt32(tb_viewIngredient1)
这是Int32无法解析的。您可以将其文本转换为int32(如果它具有数字值并且可以解析),例如:
int.Parse(tb_viewIngredient1.Text)
或
Conver.ToInt32(tb_viewIngredient1.Text)
答案 1 :(得分:0)
问题出在两个地方
MethodName( string theStringVariable,tb_1,tb_2);
private void MethodName(字符串 theStringVariable ,TextBox tb_name,TextBox tb_allergen) {
答案 2 :(得分:0)
Convert.ToInt32(tb_viewIngredient1)
将引发异常,因为您正尝试将TextBox
控件转换为int
。而是尝试将Text
的{{1}}属性传递给方法:
TextBox
答案 3 :(得分:0)
问题出在(Convert.ToInt32(tb_viewIngredient1)
中,您必须将其转换为:
(Convert.ToInt32(tb_viewIngredient1.Text)
答案 4 :(得分:0)
我在这里看到三个不同的选项。根据您的需求,这些方法甚至比固定代码更好。它们都解决了两点:
ingredientList
中的每个项目,但是文本框将仅保留列表中最后一个项目的数据。要么只看最后一个项目(不需要循环),要么使用列表中的所有项目(即:创建csv字符串)。循环很浪费,并且使代码复杂化。。
private void populateBoxesWithIngredientResults(IEnumerable<ingredient> ingredientList, TextBox tb_name, TextBox tb_allergen)
{
string nameDelimiter = "";
string allergenDelimiter = "";
string ingredients = "";
string allergens = "";
var allergenTable = {"N/A", "Nut", "Gluten", "Dairy", "Egg"};
foreach (ingredient ingredient in ingredientList)
{
//Is Convert.ToString() really needed here?
// I feel like ingredient.IngredientName is ALREADY A STRING
ingredients += delimiter + Convert.ToString(ingredient.IngredientName);
nameDelimiter = ",";
if (ingredient.AllergenID > 0 && ingredient.AllergenID < allergenTable.Length)
{
allergens += allergenDelimiter + allergenTable[ingredient.AllergenID];
allergenDelimiter = ",";
}
}
if (allergens == "") allergens = "N/A";
tb_name.Text = ingredients;
tb_allergen.Text = allergens;
}
或
private void populateBoxesWithIngredientResults(IEnumerable<ingredient> ingredientList, TextBox tb_name, TextBox tb_allergen)
{
tb_name.Text = string.Join(",", ingredientList.Select(i => i.IngredientName));
var allergenTable = {"N/A", "Nut", "Gluten", "Dairy", "Egg"};
var allergens = ingredientList.
Select(i => (i.AllergenID > 0 && i.AllergenID < allergenTable.Length)? allergenTable[i.AllergenID]):"").
Where(i => i.Length > 0);
var result = string.Join(",", allergens);
if (string.IsNullOrEmpty(result)) result = "N/A";
tb_allergen.Text = result;
}
或
private void populateBoxesWithIngredientResults(List<ingredient> ingredientList, TextBox tb_name, TextBox tb_allergen)
{
if (ingredientList.Length == 0)
{
tb_name.Text = "";
tb_allergen.Text = "";
}
var allergenTable = {"N/A", "Nut", "Gluten", "Dairy", "Egg"};
var ingredient = ingredientList[ingredientList.Count - 1];
tb_name.Text = ingredient.IngredientName;
if (ingredient.AllergenID >= 0 && ingredient.AllergenID < allergenTable.Length)
{
tb_allergen.Text = allergenTable[ingredient.AllergenID];
}
else
{
tb_allergen.Text = "N/A";
}
}