Question

我正在使用一个简单的while循环和一个数组来追逐条带上的LED。

while True:
    for i in range(nLEDs):
        R = [ 255 ] * nLEDs
        G = [ 255 ] * nLEDs
        B = [ 255 ] * nLEDs
        intensity = [ 0 ] * nLEDs
        intensity[i] = 1
        setLEDs(R, G, B, intensity)
        time.sleep(0.05)

反复追逐结束和反击的最优雅方式是什么（有点像弹跳球）？

Answer 1

很简单，您可以复制for循环。让它第二次逆转。

似乎没有必要一遍又一遍地重新定义R，G，B，所以那些可以被移出循环，但也许你打算改变那些，所以我现在把它们留在了

while True:
    for i in range(nLEDs):
        R = [ 255 ] * nLEDs
        G = [ 255 ] * nLEDs
        B = [ 255 ] * nLEDs
        intensity = [ 0 ] * nLEDs
        intensity[i] = 1
        setLEDs(R, G, B, intensity)
        time.sleep(0.05)

    for i in reversed(range(nLEDs)):
        R = [ 255 ] * nLEDs
        G = [ 255 ] * nLEDs
        B = [ 255 ] * nLEDs
        intensity = [ 0 ] * nLEDs
        intensity[i] = 1
        setLEDs(R, G, B, intensity)
        time.sleep(0.05)

理想情况下，您的API具有可以调用的setLED功能，然后您不需要在每次只更改2时设置所有LED的状态。

Answer 2

您可以将其定义为collections.deque，然后rotate

，而不是将强度定义为列表

R = [ 255 ] * nLEDs
G = [ 255 ] * nLEDs
B = [ 255 ] * nLEDs
intensity = collections.deque([ 0 ] * nLEDs)
intensity[0] = 1
while True:
    for i in range(nLEDs):
        intensity.rotate(1)
        setLEDs(R, G, B, list(intensity))
        time.sleep(0.05)

然后添加一个额外的for循环返回

LED追逐使用python

2 个答案: