Question

所以这就是我的问题，我在（非常）开始让我的Rogue像游戏一样，并且我坚持让敌人追逐玩家，它必须是一件容易而且显而易见的东西，但我的技能很低......所以这是我的怪物类

class monster():
  def __init__(self , mright, mleft, mup, mdown):
    self.mright = pygame.image.load(mright).convert_alpha()
    self.mleft = pygame.image.load(mleft).convert_alpha()
    self.mup = pygame.image.load(mup).convert_alpha()
    self.mdown = pygame.image.load(mdown).convert_alpha()

    self.sqrx = 7 
    self.sqry = 2
    self.x = 210
    self.y = 60
    self.direction = self.mdown

    char = character(right , left , up , down , Level)

def chase(self,direction):
    if self.sqrx > char.sqrx :
        self.sqrx -= 1
        self.x = self.sqrx * size_sprite 
    self.direction = self.mleft

    if self.sqrx < char.sqrx :
        self.sqrx += 1
        self.x = self.sqrx * size_sprite 
    self.direction = self.mright

    if self.sqry > char.sqry :
        self.sqry -= 1
        self.y = self.sqry * size_sprite
    self.direction = self.mup

    if self.sqry < char.sqry :
        self.sqry += 1
        self.y = self.sqry * size_sprite
    self.direction = self.mdown

游戏循环

while gameon:


    pygame.time.Clock().tick(30)

    for event in pygame.event.get():

        if event.type == QUIT:
            gameon = 0
            on = 0

        elif event.type == KEYDOWN:

            if event.key == K_ESCAPE:
                gameon = 0

            elif event.key == K_RIGHT:
                char.move('right')  
            elif event.key == K_LEFT:
                char.move('left')
            elif event.key == K_UP:
                char.move('up')
            elif event.key == K_DOWN:
                char.move('down')

    level.display(window)
    window.blit(monst.direction , (monst.x , monst.y))
    window.blit(char.direction , (char.x , char.y))
    pygame.display.flip()

Answer 1

您应该在mainloop中使用chase() - 请参阅代码中的注释

while gameon:

    pygame.time.Clock().tick(30)

    # --- events ---

    for event in pygame.event.get():

        if event.type == QUIT:
            gameon = 0
            on = 0

        elif event.type == KEYDOWN:

            if event.key == K_ESCAPE:
                gameon = 0

            elif event.key == K_RIGHT:
                char.move('right')  
            elif event.key == K_LEFT:
                char.move('left')
            elif event.key == K_UP:
                char.move('up')
            elif event.key == K_DOWN:
                char.move('down')
        # - object events ---

        # char.handle_event(event)

    # --- updates ---

    # HERE put all functions which change elements
    #      (but don't depend on events) like:
    # - chasing player, 
    # - moving mosters, 
    # - detecting collisions, 
    # - animating other elements (ie. fire, water, etc.)

    # --- draws all elements ---

    level.display(window)
    window.blit(monst.direction , (monst.x , monst.y))
    window.blit(char.direction , (char.x , char.y))
    pygame.display.flip()

查看一些templates of PyGame code

在Moster中我会使用char（玩家实例）作为

中的参数

def __init__(self , char, ...):
    self.char = char

始终可以访问其位置

或至少

def chase(self, direction, char):

在您拨打chase()

时可以访问播放器

BTW：而不是gameon = 0更具可读性gameon = False（和gameon = True）

您可以在draw()中创建Moster()并执行

 monst.draw(window)

而不是

 window.blit(monst.direction , (monst.x , monst.y))

对变量（CamelCase）的类（class Monster():）和lower_case名称使用moster = Moster()名称。它使代码更具可读性。见PEP 8 -- Style Guide for Python Code

Answer 2

就像上面提到的那样 - 你设置方向的缩进使得每次调用chase时它都会调用所有4个赋值。这基本上总是设置direction = self.mdown

def chase(self,direction):
    if self.sqrx > char.sqrx :
        self.sqrx -= 1
        self.x = self.sqrx * size_sprite 
        self.direction = self.mleft

怪物追逐pygame

2 个答案: