Question

我有一个递归语法，并希望从它的不同规则开始解析。是不是可以多次重写相同的语法？

示例：我有json解析器：

template <typename It, typename Skipper = qi::space_type>
struct grammar : qi::grammar<It, value (), Skipper>
{
  grammar () : grammar::base_type (value_)
  {
    using namespace qi;

    static auto const null_ = proto::deep_copy ("null" >> qi::attr (null {}));

    static auto const bool_ = proto::deep_copy (
      "true" >> qi::attr (true) | "false" >> qi::attr (false));

    static auto const text_ = proto::deep_copy (
      '"' >> qi::raw [*('\\' >> qi::char_ | ~qi::char_('"'))] >> '"');

    value_  = null_ | bool_ | text_ | double_ | object_ | array_;
    member_ = text_ >> ':' >> value_;
    object_ = '{' >> -(member_ % ',') >> '}';
    array_  = '[' >> -(value_ % ',') >> ']';

    BOOST_SPIRIT_DEBUG_NODES((value_)(member_)(object_)(array_))
  }

private:
  qi::rule<It, json:: value (), Skipper> value_;
  qi::rule<It, json::member (), Skipper> member_;
  qi::rule<It, json::object (), Skipper> object_;
  qi::rule<It, json:: array (), Skipper> array_;
};

通常我需要将输入解析为json value ，但有时我需要将其解析为json array 或json object 。我可以不重写相同的语法，而这些语法之间的唯一区别是入口点吗？

Answer 1

我发现最接近的解决方案是将语法拆分为基类和派生类，并在派生类中使用不同的启动规则。它不会重复复制源代码，但仍然看起来像是超重解决方案。

template <typename It, typename Data, typename Skipper = qi::space_type>
struct base : qi::grammar<It, Data (), Skipper>
{
  using jbase_type = base;

  template <typename Member>
  base (Member& member) : base::base_type (member)
  {
    using namespace qi;
    using namespace Json;

    value_  = null_ | bool_ | text_ | double_ | object_ | array_;
    member_ = text_ >> ':' >> value_;
    object_ = '{' >> -(member_ % ',') >> '}';
    array_  = '[' >> -(value_ % ',') >> ']';

    BOOST_SPIRIT_DEBUG_NODES((value_)(member_)(object_)(array_))
  }

protected:
  escaped_string_grammar<It> text_;

  qi::rule<It, Json:: Value (), Skipper> value_;
  qi::rule<It, Json::Member (), Skipper> member_;
  qi::rule<It, Json::Object (), Skipper> object_;
  qi::rule<It, Json:: Array (), Skipper> array_;
};

//++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++//
template <typename It, typename Skipper = qi::space_type>
struct value : base<It, Json::Value, Skipper>
{
  value () : value::jbase_type (value::jbase_type::value_) {}
};

//++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++//
template <typename It, typename Skipper = qi::space_type>
struct array : base<It, Json::Array, Skipper>
{
  array () : array::jbase_type (array::jbase_type::array_) {}
};

//++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++//
template <typename It, typename Skipper = qi::space_type>
struct object : base<It, Json::Object, Skipper>
{
  object () : object::jbase_type (object::jbase_type::object_) {}
};

Boost.Spirit Qi：同一语法的不同入口点？

1 个答案: