Question

using UnityEngine;
using System.Collections;

public class GameRootScript : MonoBehaviour {

    public GameObject prefab = null;

    private AudioSource audio;
    public AudioClip jumpSound;

    public Texture2D icon = null;
    public static string mes_text = "test";


    // Use this for initialization
    void Start () {
        this.audio = this.gameObject.AddComponent<AudioSource> ();
        this.audio.clip = this.jumpSound;
        this.audio.loop = false;
    }

    void onGUI()
    {
        Debug.Log ("Image");
        GUI.DrawTexture (new Rect (Screen.width/2, 64, 64, 64), icon);
        GUI.Label (new Rect (Screen.width / 2, 128, 128, 32), mes_text);
    }

    // Update is called once per frame
    void Update () {
        if(Input.GetKeyDown (KeyCode.Z)){
            Debug.Log("Prefab");
            GameObject go = GameObject.Instantiate(this.prefab) as GameObject;
            go.transform.position = new Vector3(Random.Range(-2.0f,2.0f), 1.0f, 1.0f);

            this.audio.Play();
        }
    }
}

我在Unity中创建了onGUI（）方法，但该方法不起作用我只是按照这本书，我不知道是什么原因造成的即使我编译该代码也没有错误书籍版本为4.xx，Unity版本为5.1.2。

Answer 1

您的onGUI方法存在拼写错误。它应该是OnGUI，大写“O”。

即使编译了拼写错误，Unity引擎也基本上忽略了这种方法。

如何在Unity中创建onGUI方法？

1 个答案: