Question

所以我此刻试图解码一个websocket消息帧，就是这样一个例子，

0x81 0x85 0x37 0xfa 0x21 0x3d 0x7f 0x9f 0x4d 0x51 0x58（包含＆＃34; Hello＆＃34;）

   0                   1                   2                   3
   0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1
  +-+-+-+-+-------+-+-------------+-------------------------------+
  |F|R|R|R| opcode|M| Payload len |    Extended payload length    |
  |I|S|S|S|  (4)  |A|     (7)     |             (16/64)           |
  |N|V|V|V|       |S|             |   (if payload len==126/127)   |
  | |1|2|3|       |K|             |                               |
  +-+-+-+-+-------+-+-------------+ - - - - - - - - - - - - - - - +
  |     Extended payload length continued, if payload len == 127  |
  + - - - - - - - - - - - - - - - +-------------------------------+
  |                               |Masking-key, if MASK set to 1  |
  +-------------------------------+-------------------------------+
  | Masking-key (continued)       |          Payload Data         |
  +-------------------------------- - - - - - - - - - - - - - - - +
  :                     Payload Data continued ...                :
  + - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - +
  |                     Payload Data continued ...                |
  +---------------------------------------------------------------+

所以有效载荷位出现为0100001 = 33.肯定应该是5？或者我错过了什么？

编辑：标题位的值到＆＃34; Payload len＆＃34;是，

1000000110100001
[1][0][0][0][0001][1][0100001]

尼克。

Answer 1

好吧，我是愚蠢的，它是位，而不是字节！

WebSockets消息帧长度应该是5，但是得到33

1 个答案: