嘿伙计们,所以我试图从蓝牙设备中读取连续流整数的流:
-11
121
123
1234
-11
我在网上找到了一些代码,但是为了做一些处理,数字需要是字符串而不是字符串,parseInt占用了太多的CPU,我尝试使用缓冲流而无济于事。
这是目前的方法:
void beginListenForData()
{
final Handler handler = new Handler();
final byte delimiter = 10; //This is the ASCII code for a newline character
stopWorker = false;
readBufferPosition = 0;
readBuffer = new byte[1024];
workerThread = new Thread(new Runnable()
{
public void run()
{
while(!Thread.currentThread().isInterrupted() && !stopWorker)
{
try
{
int bytesAvailable = mmInputStream.available();
if(bytesAvailable > 0)
{
byte[] packetBytes = new byte[bytesAvailable];
mmInputStream.read(packetBytes);
for(int i=0;i<bytesAvailable;i++)
{
byte b = packetBytes[i];
if(b == delimiter)
{
byte[] encodedBytes = new byte[readBufferPosition];
System.arraycopy(readBuffer, 0, encodedBytes, 0, encodedBytes.length);
final String data = new String(encodedBytes, "US-ASCII");
readBufferPosition = 0;
handler.post(new Runnable()
{
public void run()
{
myLabel.setText(data);
}
});
}
else
{
readBuffer[readBufferPosition++] = b;
}
}
}
}
catch (IOException ex)
{
stopWorker = true;
}
}
}
});
workerThread.start();
}
如果它有所不同,数据来自Arudino,我可以修改它的流式传输方式。
谢谢!
答案 0 :(得分:0)
使用DataInputStream
BufferedInputStream
和readInt()
方法。这假设网络字节顺序当然是整数。
忘记所有这些arraycopy()
内容。