我想从Haskell中的可能图片中提取每个RGB值。
获取原始值(0-255)的最简单方法是什么?
我已经在Juicy Pixels库中获得了一些结果,但不知怎的,我总是得到例外:
*** Exception: ./Data/Vector/Generic.hs:249 ((!)): index out of bounds (660000,660000)
这是相应的代码。
{-# LANGUAGE TypeSynonymInstances #-}
module Main where
import Codec.Picture (readImage, pixelAt, PixelRGB8(..))
import Codec.Picture.Types
import System.FilePath.Posix (splitExtension)
toRGBRaw :: FilePath -> IO ()
toRGBRaw fp = do
image <- readImage fp
case image of
Left _ -> putStrLn $ "Sorry, not a supported codec for " ++ fp
Right dynimg -> do
let imgrgba8 = fromDynamicImage dynimg
let (name, _) = splitExtension fp
writeFile (name ++ ".txt") (concat $ accumPixels imgrgba8)
accumPixels :: Image PixelRGBA8 -> [String]
accumPixels img@(Image w h _) = [ format (pixelAt img x y) x y | x <- [0..w], y <- [0..h]]
where format (PixelRGBA8 r g b _) j k = "#" ++ show r ++ "$"
++ show g ++ "$"
++ show b ++ "$"
++ show j ++ "$"
++ show k ++ "*\n"
-- Copied from
-- See http://hackage.haskell.org/package/JuicyPixels-util-0.2/docs/Codec-Picture-RGBA8.html
class ToPixelRGBA8 a where
toRGBA8 :: a -> PixelRGBA8
instance ToPixelRGBA8 Pixel8 where
toRGBA8 b = PixelRGBA8 b b b 255
instance ToPixelRGBA8 PixelYA8 where
toRGBA8 (PixelYA8 l a) = PixelRGBA8 l l l a
instance ToPixelRGBA8 PixelRGB8 where
toRGBA8 (PixelRGB8 r g b) = PixelRGBA8 r g b 255
instance ToPixelRGBA8 PixelRGBA8 where
toRGBA8 = id
fromDynamicImage :: DynamicImage -> Image PixelRGBA8
fromDynamicImage (ImageY8 img) = pixelMap toRGBA8 img
fromDynamicImage (ImageYA8 img) = pixelMap toRGBA8 img
fromDynamicImage (ImageRGB8 img) = pixelMap toRGBA8 img
fromDynamicImage (ImageRGBA8 img) = img
-- end of Codec.Picture.RGBA8
这是一个示例图片:Link
代码目前有点无序,因为我必须复制Codec.Picture.RGBA8
的一些定义,这些定义不能通过LTS获得。不要介意字符串表示,我通过带有WiFi盾牌的Arduino解析它们。
答案 0 :(得分:4)
accumPixels
中的列表理解是0索引的,但也包括边界。这可能是个问题。在Haskell中,[0..3]
是列表[0,1,2,3]
,因此您可能指的是[0..(w-1)]
和[0..(h-1)]
。