我目前正在从事计算机科学任务,并且已经达到了一个我无法解决的问题。我已经提供了代码,我要编辑它以完成我迄今为止能够完成的某些事情,但我似乎无法获得下一个。该代码从标准输入中读取许多学生姓名和年龄,直到EOF(控制D等)终止,构建它们的链接列表。从每个输入行读取一个学生。 到目前为止我的代码是:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
#define MAX_LINE_LENGTH 80 // The longest line this program will accept
#define MAX_NUM_STUDENTS 500 // The maximum number of students this program can handle
#define MAX_NAME_SIZE 50 // The maximum allowable name length
// The declaration of the student record (or struct). Note that
// the struct contains the name as an array of characters, rather than
// containing just a pointer to the name as before.
typedef struct student_s Student;
struct student_s {
char name[MAX_NAME_SIZE];
int age;
Student* next; // Pointer to next student in a list
};
// Create a pool of student records to be allocated on demand
Student studentPool[MAX_NUM_STUDENTS]; // The student pool
int firstFree = 0;
// Return a pointer to a new student record from the pool, after
// filling in the provided name and age fields. Returns NULL if
// the student pool is exhausted.
Student* newStudent(const char* name, int age) {
Student* student = NULL;
if (firstFree < MAX_NUM_STUDENTS) {
student = &studentPool[firstFree];
firstFree += 1;
strncpy(student->name, name, MAX_NAME_SIZE);
student->name[MAX_NAME_SIZE - 1] = '\0'; // Make sure it's terminated
student->age = age;
student->next = NULL;
}
return student;
}
// Read a single student from a csv input file with student name in first column,
// and student age in second.
// Returns: A pointer to a Student record, or NULL if EOF or an invalid
// student record is read. Blank lines, or lines in which the name is
// longer than the provided name buffer, or there is no comma in the line
// are considered invalid.
Student* readOneStudent(FILE* file)
{
char buffer[MAX_LINE_LENGTH]; // Buffer into which we read a line from stdin
Student* student = NULL; // Pointer to a student record from the pool
// Read a line, extract name and age
char* cp = fgets(buffer, MAX_LINE_LENGTH, file);
if (cp != NULL) { // Proceed only if we read something
char* commaPos = strchr(buffer, ',');
if (commaPos != NULL && commaPos > buffer) {
int age = atoi(commaPos + 1);
*commaPos = '\0'; // null-terminate the name
student = newStudent(buffer, age);
}
}
return student;
}
// Reads a list of students from a given file. Input stops when
// a blank line is read, or an EOF occurs, or an illegal input
// line is encountered.
// Returns a pointer to the first student in the list or NULL if no
// valid student records could be read.
Student* readStudents(FILE *file)
{
Student* first = NULL; // Pointer to the first student in the list
Student* last = NULL; // Pointer to the last student in the list
Student* student = readOneStudent(file);
while (student != NULL) {
if (first == NULL) {
first = last = student; // Empty list case
}
else {
last->next = student;
last = student;
}
student= readOneStudent(file);
}
return first;
}
// printOneStudent: prints a single student, passed by value
void printOneStudent(Student student)
{
printf("%d (%s)\n", student.age, student.name);
}
// printStudents: print all students in a list of students, passed
// by reference
void printStudents(const Student* student)
{
while (student != NULL) {
printOneStudent(*student);
student = student->next;
}
}
int main(void)
{
FILE* inputFile = stdin;
if (inputFile == NULL) {
fprintf(stderr, "File not found\n");
}
else {
Student* studentList = readStudents(inputFile);
printStudents(studentList);
}
}
需要做的代码是获取输入列表,例如:
21, Fred Nurk
92, Arwen Evensong
并按如下方式返回学生名单:
Fred Nurk (21)
Arwen Evensong (92)
但是我的代码返回:
0 (21)
0 (92)
我无法理解为什么。输入已设置且无法更改,必须对代码进行任何编辑。
答案 0 :(得分:1)
在您的函数Student* readOneStudent(FILE* file);
中,您希望以这种格式输入:
Fred Nurk,21
Arwen Evensong,92
如果您希望输入采用以下形式:
21, Fred Nurk
92, Arwen Evensong
然后这可能会有所帮助:
Student* readOneStudent(FILE* file)
{
char *buffer; // Buffer into which we read a line from stdin
buffer = (char *)malloc(MAX_LINE_LENGTH);
Student* student = NULL; // Pointer to a student record from the pool
// Read a line, extract name and age
char* cp = fgets(buffer, MAX_LINE_LENGTH, file);
if (cp != NULL) { // Proceed only if we read something
char* commaPos = strchr(buffer, ',');
if (commaPos != NULL && commaPos > buffer) {
buffer[strlen(buffer)-1] = '\0';
*commaPos = '\0'; // null-terminate the age part
int age = atoi(buffer);
student = newStudent(commaPos+2, age);
}
}
return student;
}
编辑:
void printOneStudent(Student student)
{
printf("%s (%d)\n", student.name, student.age);
}
答案 1 :(得分:0)
让我们检查以下代码段
Student* readOneStudent(FILE* file)
{
char buffer[MAX_LINE_LENGTH]; // Buffer into which we read a line from stdin
Student* student = NULL; // Pointer to a student record from the pool
// Read a line, extract name and age
char* cp = fgets(buffer, MAX_LINE_LENGTH, file);
if (cp != NULL) { // Proceed only if we read something
char* commaPos = strchr(buffer, ',');
if (commaPos != NULL && commaPos > buffer) {
int age = atoi(commaPos + 1);
*commaPos = '\0'; // null-terminate the name
student = newStudent(buffer, age);
}
}
return student;
}
根据你的说法,输入应该是:
年龄,姓名
以下行找到逗号分隔符的地址
char* commaPos = strchr(buffer, ',');
年龄正在通过以下方式提取:
int age = atoi(commaPos + 1);
因此它占用逗号分隔符的地址并递增1
年龄,[N] AME
因此,您的假设是不正确的。输入应该是颠倒的顺序
姓名,年龄
输出将是
年龄(姓名)
编辑: 要交换输入表单,只需交换到Student * readOneStudent(FILE *文件)中的以下内容:
int age = atoi(buffer);
student = newStudent(commaPos + 1, age);
并在void printOneStudent(学生)中交换输出表格:
printf("%s (%d)\n", student.name, student.age);