Question

#define HASH_SIZE 5

// prototype
int hash(char *word);

// counter
int counter;

// node
typedef struct node
{
    char word[LENGTH + 1];
    struct node *next;
} node;

// hash table
struct node *hashtable[HASH_SIZE];
  bool
load(const char *dictionary)
{
    // open the dictionary
    FILE *dict = fopen(dictionary, "r");
    if(dict == NULL)
    {
        printf("Could not open %s.\n", dictionary);
        return false;
    }

    // set all values in the hash table to null
    for(int i = 0; i < HASH_SIZE; i++)
    {
        hashtable[i] = NULL;
    }

    // set the counter to 0
    counter = 0;

    // iterate through the words in the dictionary
    while (!feof(dict))
    {
        //declare a node
        node *n = malloc( sizeof(node) );

        // copy the word into the node
        fscanf(dict, "%s", n.word);

        // hash the word
        int hash_value = hash(n.word);

        // start saving addresses to the hashtable
        n.next = hashtable[hash_value];
        hashtable[hash_value] = &n;

        // that's one more!
        counter++;
    }


    fclose(dict);

    return true;
}

以下几行：

        //declare a node
    node *n = malloc( sizeof(node) );

// hash the word
    int hash_value = hash(n.word);

    // start saving addresses to the hashtable
    n.next = hashtable[hash_value];
    hashtable[hash_value] = &n;r code here

我收到以下错误消息：

dictionary.c：在函数'load'中：
dictionary.c：112：29：错误：在非结构或联合的事物中请求成员'word' dictionary.c：135：32：错误：在非结构或联合的事物中请求成员'word' dictionary.c：138：10：错误：在非结构或联合的事物中请求成员'next' dictionary.c：139：31：错误：从不兼容的指针类型[-Werror]
分配

问题是什么？

Answer 1

非常简单：

node *n = malloc( sizeof(node) );
fscanf(dict, "%s", n.word);

n是指向node的指针，但n.word表示n本身是node。对于指针，语法略有不同。

fscanf(dict, "%s", n->word);

不兼容的指针类型和结构问题

1 个答案: