Question

我在最新的Raspberry Pi上使用Debian附带的Python3.2：

try:
   headers = {
      'Content-Type': 'application/json',
      'Connection': 'close',
   }
   s = requests.session()
   s.keep_alive = False

   response = s.get('http://example.com/', headers=headers, timeout=1)
except Exception as e:
   s.close()
   print(repr(e))

服务器没有及时回复，因此脚本超时，并引发异常。但是，客户端会使连接保持打开状态。

我想在超时发生后关闭连接？

我理解TCP协议级别的概念，但我没有在网上看到任何关于如何在python请求中执行简单操作的文档。

Answer 1

Wrap it in a with statement, then move the s.close() to a finally: after the except:

with requests.session() as s:
    s.keep_alive = False
    try:
       headers = {
          'Content-Type': 'application/json',
          'Connection': 'close',
       }

       response = s.get('http://example.com/', headers=headers, timeout=1)
    except Exception as e:
       print(repr(e))
    finally:
       s.close()

The s.close() will run every time, whether it succeeds or fails. the with statement should provide the extra insurance since the whole thing will run in that context

Answer 2

I'm assuming you're seeing these connections in something like tcpdump.

TCP connections linger (in the kernel) by design, for a period of time. There's really nothing you can do about it.

Python请求在超时后不关闭TCP连接

2 个答案: