Question

我有一个像这样的ES6方法：

/**
* Builds a knex object with offset and limit
* @param {Object} pagination
* @param {number} pagination.count - limit query to
* @param {number} pagination.start - start query at
* @returns {QueryBuilder}
*/
buildPagination (pagination) {
    if (_.isEmpty(pagination)) {
        return this;
    }

    let count = pagination.count;
    let start = pagination.start;

    this.knex = this.knex.offset(start);

    if (count !== undefined) {
        this.knex = this.knex.limit(count);
    }

    return this;
}

我的测试看起来像：

describe("#buildPagination", () => {
    let knex;
    let b;
    let pagination;

    beforeEach(() => {
        knex = sinon.stub();
        knex.offset = sinon.stub();
        knex.limit = sinon.stub();
        b = new QueryBuilder(knex);
        pagination = {
            start: 3,
            count: 25
        };
    });

    it.only("should attach limit and offset to knex object", () => {
        let res = b.buildPagination(pagination).knex;

        console.log(res);

        assert(res.offset.calledOnce);
        assert(res.offset.calledWith(3));
        assert(res.limit.calledAfter(res.offset))
        // assert(res.knex.limit.calledWith(25));
    });
});

我遇到的错误是TypeError: Cannot read property 'limit' of undefined。此行发生错误：this.knex = this.knex.limit(count);

Answer 1

这是一个独立的演示：

var knex    = sinon.stub();  
knex.limit  = sinon.stub();
knex.offset = sinon.stub();

knex = knex.offset();

此时，knex为undefined，因为您的存根实际上并未返回任何内容。当您随后致电knex.limit()时，您会收到TypeError。

如果要允许链接，则方法存根需要返回knex存根：

knex.limit  = sinon.stub().returns(knex);
knex.offset = sinon.stub().returns(knex);

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