在python

Question

我不知道如何编写用于比较列表中存在的两个字典的脚本，即使我不知道字典名称

示例代码： 我是否正确？如果没有那么请帮我找到解决方案 这里“dct_list_cluster”是包含两个词典的列表

码

for count in range(len(dct_list_cluster)):
  if dct_list_cluster[count].keys() in dct_list_cluster[count+1].keys():
     fo = open("cluster_" + str(ip_list[count]) + "_output.txt", "a")
     fo.write("\n=> %s" % (dct_list_cluster[key])

Answer 1

如果我说对了你

您可以使用list comprehension

<强>码

lst=[{"a":2,"b":3,"c":4},{"b":4}]
[a for a in lst[0] if a in lst[1]]
['b']

完成list comprehension

<强>码

lst=[{"a":2,"b":3,"c":4},{"b":4}]
for a in lst[0]:
    if a in lst[1]]:
        print a

<强>输出：

b

<强>操作：

1.当你在字典上循环时，你正在循环遍历字典的键there are methods to loop over value and both keys and value

2.如果是第二个字典，请查看是否可以打印

修改

lst=[{"a":2,"b":3,"c":4},{"b":4},{"b":2,"d":6},{"d":4}]


for count in range(len(lst)-1):
   for a in lst[count]:
      if a in lst[count+1]:
         print "dic"+str(count)+"\t"+str(a)+"\tis common to next dic"

<强>输出：

dic0    b       is common to next dic
dic1    b       is common to next dic
dic2    d       is common to next dic