Question

我编写了此函数来比较两个字典值。我在另一个函数中使用第一个函数的输出，但是出现了

错误

global variable not defined

这是我的第一个功能：

a = {'file_1.txt': 1235, 'file_3.txt': 2453, 'file_2.txt': 2345}
b = {'file_1.txt': 1245, 'file_2.txt': 2345, 'file_3.txt': 2453}

def compfunc(): 
    if a == b: 
        return ("Passed")
    elif a != b:
        return ("Failed")

result = compfunc()
result

这是我在另一堂课中的第二个功能：

def recordcountcomp(self):
    for output in result:
        logger.info("The Results: %s" %output, also_console=True)

如何在函数中使结果全局化？

Answer 1

在int solution(vector<int> &A) { // Find prefix sum. int N = A.size(); vector<int> ps(N + 1, 0); for (int i = 1; i <= N; i++) { ps[i] = A[i - 1] + ps[i - 1]; } int lft_idx, min_lft_idx; double avg_here, min_avg, avg_of_two, avg_with_prev; // Initialize variables at the first possible slice (A[0:1]). lft_idx = min_lft_idx = 0; avg_here = min_avg = (A[0] + A[1]) / 2.0; // Find min average of every slice that ends at ith element, // starting at i = 2. for (int i = 2; i < N; i ++) { // average of A[lft_idx : i] avg_with_prev = ((double) ps[i + 1] - ps[lft_idx]) / (i - lft_idx + 1); // average of A[i - 1 : i] avg_of_two = (A[i - 1] + A[i]) / 2.0; // Find minimum and update lft_idx of slice // (previous lft_idx or i - 1). if (avg_of_two < avg_with_prev) { avg_here = avg_of_two; lft_idx = i - 1; } else avg_here = avg_with_prev; // Keep track of minimum so far and its left index. if (avg_here < min_avg) { min_avg = avg_here; min_lft_idx = lft_idx; } } return min_lft_idx; }函数的第一行插入global result，以便python解释器知道要在其中搜索recordcountcomp的范围。

比较两个字典的全局变量

1 个答案: