Question

我想从“http：x.x.x.x / test / test.jsp？[parama]”groovy中调用一个url。在这个文件中，我从url和furhter处理params值我自己的方式。但是如何从groovy中调用这个url。我是groovy的新手。我试过这个，但它不起作用：

URL url = new URL("http://192.168.1.87:8080/bridge/test.php");
URLConnection conn = url.openConnection();

Answer 1

此代码适用于我：

def url = new URL("http://X.X.X.X:8080/url?[params]")
HttpURLConnection connection = (HttpURLConnection) url.openConnection()
connection.setRequestMethod("GET")
// connection.setConnectTimeout(10000)
connection.connect()
if (connection.responseCode == 200 || connection.responseCode == 201) {
    def returnMessage = connection.content
} else {
}

参考：Connection timeout with HttpURLConnection in Groovy

如何在常规中执行url？

1 个答案: