Question

我正在尝试制作一个柜台，显示我们前往欧洲旅行的天数。这只是大约70天（截至今天），所以我不相信我应该担心天文数字或任何东西，但我真的很难过 - 我附上了一些朋友给我的代码，也没工作。相信我，当我说我已经尝试了所有我能想到的东西 - 在任何人咬我的头之前，我已经在这些论坛上看到了，是的，我确实看了很多苹果文档，但我不是100％确定从哪里开始 - 我已经尝试过NSTimer，NSDate及其所有子类和方法，但没有任何东西可以立即跳出来。

就我认为我应该做的事情而言，我认为我需要以某种方式为今天/现在/当天的“日”分配一个整数值，这将使用[NSDate date]动态变化然后我们离开的日期相同。倒计时只是在再次调用方法时更新（如果需要，我可以使用NSTimer执行此操作）并且倒计时显示的值是这两个值之间的差异。

我并不特别希望有一种闪烁的东西在我们离开之前每秒更新一次 - 我个人认为这很俗气，但如果有人知道我会如何欣赏它以供将来参考。

我也对Google进行了大量搜索，我可能只是使用了错误的搜索字词，但我也找不到任何内容。

非常感谢任何帮助。

非常感谢。

Michaeljvdw

- (void)countDownMethod {
NSDateComponents *comps = [[NSDateComponents alloc] init];
[comps setDay:startDay];
[comps setMonth:startMonth];
[comps setYear:startYear];
[comps setHour:startHour];

NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *date = [gregorian dateFromComponents:comps];
NSLog(@"%@",date);
[gregorian release];
[comps release];
NSTimeInterval diff = [date timeIntervalSinceNow];

int diffInt = diff;

NSString *days = [NSString stringWithFormat:@"%d",diffInt/86400];
day0.text = @"0";   
day1.text = @"0";
day2.text = @"0";
NSLog(@"Days Length: %d",days.length);

if(days.length >= 1){
    day2.text = [days substringFromIndex:days.length - 1];

    if(days.length >= 2){
        day1.text = [days substringWithRange:NSMakeRange(days.length - 2, 1)];

        if(days.length >= 3){
            day0.text = [days substringWithRange:NSMakeRange(days.length - 3, 1)];
        }
    }
}

NSString *hours = [NSString stringWithFormat:@"%d",(diffInt%86400)/3600];
hour0.text = @"0";
hour1.text = @"0";
NSLog(@"Hours Length: %d",hours.length);

if(hours.length >= 1){
    hour1.text = [hours substringFromIndex:hours.length - 1];

    if(hours.length >= 2){
        hour0.text = [hours substringWithRange:NSMakeRange(hours.length - 2, 1)];
    }
}
NSString *minutes = [NSString stringWithFormat:@"%d",((diffInt%86400)%3600)/60];
minute0.text = @"0";
minute1.text = @"0";
NSLog(@"Minutes Length: %d",minutes.length);

if(minutes.length >= 1){
    minute1.text = [minutes substringFromIndex:minutes.length - 1];

    if(minutes.length >= 2){
        minute0.text = [minutes substringWithRange:NSMakeRange(minutes.length - 2, 1)];
    }
}

}

Answer 1

如果您知道2个日期（您的NSTimeInterval）之间的秒数时间，那么您可以轻松地将其转换为格式为days：hours：mins：secs的字符串，如下所示。

- (NSString*)secsToDaysHoursMinutesSecondsString:(NSTimeInterval)theSeconds {
div_t r1 = div(theSeconds, 60*60*24);
NSInteger theDays = r1.quot;
NSInteger secsLeftFromDays = r1.rem;

div_t r2 = div(secsLeftFromDays, 60*60);
NSInteger theHours = r2.quot;
NSInteger secsLeftFromHours = r2.rem;

div_t r3 = div(secsLeftFromHours, 60);
NSInteger theMins = r3.quot;
NSInteger theSecs = r3.rem;

NSString* days;
if (theDays < 10) { // make it 2 digits
    days = [NSString stringWithFormat:@"0%i", theDays];
} else {
    days = [NSString stringWithFormat:@"%i", theDays];
}

NSString* hours;
if (theHours < 10) { // make it 2 digits
    hours = [NSString stringWithFormat:@"0%i", theHours];
} else {
    hours = [NSString stringWithFormat:@"%i", theHours];
}

NSString* mins;
if (theMins < 10) { // make it 2 digits
    mins = [NSString stringWithFormat:@"0%i", theMins];
} else {
    mins = [NSString stringWithFormat:@"%i", theMins];
}

NSString* secs;
if (theSecs < 10) { // make it 2 digits
    secs = [NSString stringWithFormat:@"0%i", theSecs];
} else {
    secs = [NSString stringWithFormat:@"%i", theSecs];
}

return [NSString stringWithFormat:@"%@:%@:%@:%@", days, hours, mins,secs];
}

Answer 2

    //Another simple way  to get the numbers of days difference to a future day from today.

NSTimeInterval todaysDiff = [todayDate timeIntervalSinceNow];
NSTimeInterval futureDiff = [futureDate timeIntervalSinceNow];
NSTimeInterval dateDiff = futureDiff - todaysDiff;

div_t r1 = div(dateDiff, 60*60*24);
NSInteger theDays = r1.quot;

label.text = [NSString stringWithFormat:@"%i", theDays];

倒计时 - iPhone Count Down Timer

2 个答案: