(Single line) command to join list of lists, where the inner list are joined by spaces and the outer lists are joined by '\n'

Question

Is there a way I can join a list of of lists, where the inner list are joined by spaces and the outer lists are joined by '\n'? Is it possible to do this in a single line?

Example input:

>>> a = [[1,2,3],[2,3,4]]

Desired output:

1 2 3
2 3 4

What I've tried:

>>> ' '.join([str(s) for s in [l for l in a]])
'[1, 2, 3] [2, 3, 4]'

>>> ' '.join([str(s) for s in [l.append('\n') for l in a]])
'None None'

>>> a = [[1,2,3],[2,3,4]]
>>> [l.append('\n') for l in a]
>>> ' '.join([str(s) for s in [l for l in a]])
"[1, 2, 3, '\\n'] [2, 3, 4, '\\n']"

Answer 1

您需要使用两个连接函数。

'\n'.join(' '.join(str(j) for j in i) for i in a)

示例：

>>> print('\n'.join(' '.join(str(j) for j in i) for i in a))
1 2 3
2 3 4
>>> 

Answer 2

怎么样：

print '\n'.join([' '.join([str(i) for i in b]) for b in a])

Answer 3

试试这个 -

print('\n'.join([' '.join(map(str, x)) for x in a]))

这使用'\n'加入子列表，使用' '（空格）加入内部列表中的每个元素。

示例/演示 -

>>> a = [[1,2,3],[2,3,4]]
>>> print('\n'.join([' '.join(map(str, x)) for x in a]))
1 2 3
2 3 4