我们是否可以使用SQL查询来查看SQl Server中的表和索引大小。
SQL Server如何维护表/索引的内存使用量?
答案 0 :(得分:109)
sp_spaceused为您提供所有索引组合的大小。
如果您想要表的每个索引的大小,请使用以下两个查询之一:
SELECT
i.name AS IndexName,
SUM(s.used_page_count) * 8 AS IndexSizeKB
FROM sys.dm_db_partition_stats AS s
JOIN sys.indexes AS i
ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
WHERE s.[object_id] = object_id('dbo.TableName')
GROUP BY i.name
ORDER BY i.name
SELECT
i.name AS IndexName,
SUM(page_count * 8) AS IndexSizeKB
FROM sys.dm_db_index_physical_stats(
db_id(), object_id('dbo.TableName'), NULL, NULL, 'DETAILED') AS s
JOIN sys.indexes AS i
ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
GROUP BY i.name
ORDER BY i.name
结果通常略有不同,但在1%以内。
答案 1 :(得分:67)
exec sp_spaceused
不带参数显示整个数据库的摘要。 foreachtable解决方案为每个表生成一个结果集 - 如果您有太多表,SSMS可能无法处理。
我创建了一个script,它通过sp_spaceused
收集表格信息,并在一个记录集中显示摘要,按大小排序。
create table #t
(
name nvarchar(128),
rows varchar(50),
reserved varchar(50),
data varchar(50),
index_size varchar(50),
unused varchar(50)
)
declare @id nvarchar(128)
declare c cursor for
select '[' + sc.name + '].[' + s.name + ']' FROM sysobjects s INNER JOIN sys.schemas sc ON s.uid = sc.schema_id where s.xtype='U'
open c
fetch c into @id
while @@fetch_status = 0 begin
insert into #t
exec sp_spaceused @id
fetch c into @id
end
close c
deallocate c
select * from #t
order by convert(int, substring(data, 1, len(data)-3)) desc
drop table #t
答案 2 :(得分:20)
在SQL 2012上,在表级获取此信息变得非常简单:
SQL Management Studio - >右键单击Db - >报告 - >标准报告 - >按表使用磁盘!
享受
答案 3 :(得分:13)
EXEC sp_MSforeachtable @command1="EXEC sp_spaceused '?'"
答案 4 :(得分:3)
这是最成功答案的更紧凑版本:
create table #tbl(
name nvarchar(128),
rows varchar(50),
reserved varchar(50),
data varchar(50),
index_size varchar(50),
unused varchar(50)
)
exec sp_msforeachtable 'insert into #tbl exec sp_spaceused [?]'
select * from #tbl
order by convert(int, substring(data, 1, len(data)-3)) desc
drop table #tbl
答案 5 :(得分:3)
自创建这篇文章以来已经很长时间了,但我想分享我的剧本:
WITH CteIndex
AS
(
SELECT
reservedpages = (reserved_page_count)
,usedpages = (used_page_count)
,pages = (
CASE
WHEN (s.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
ELSE lob_used_page_count + row_overflow_used_page_count
END
)
,s.object_id
,i.index_id
,i.type_desc AS IndexType
,i.name AS indexname
FROM sys.dm_db_partition_stats s
INNER JOIN sys.indexes i ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
)
SELECT DISTINCT
DB_NAME(DB_ID()) AS DatabaseName
,o.name AS TableName
,o.object_id
,ct.indexname
,ct.IndexType
,ct.index_id
, IndexSpace = LTRIM (STR ((CASE WHEN usedpages > pages THEN CASE WHEN ct.index_id < 2 THEN pages ELSE (usedpages - pages) END ELSE 0 END) * 8, 15, 0) + ' KB')
FROM CteIndex ct
INNER JOIN sys.objects o ON o.object_id = ct.object_id
INNER JOIN sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL, NULL , NULL) ps ON ps.object_id = o.object_id
AND ps.index_id = ct.index_id
ORDER BY name ASC
适用于:
答案 6 :(得分:2)
--Gets the size of each index for the specified table
DECLARE @TableName sysname = N'SomeTable';
SELECT i.name AS IndexName
,8 * SUM(s.used_page_count) AS IndexSizeKB
FROM sys.indexes AS i
INNER JOIN sys.dm_db_partition_stats AS s
ON i.[object_id] = s.[object_id] AND i.index_id = s.index_id
WHERE s.[object_id] = OBJECT_ID(@TableName, N'U')
GROUP BY i.name
ORDER BY i.name;
SELECT i.name AS IndexName
,8 * SUM(a.used_pages) AS IndexSizeKB
FROM sys.indexes AS i
INNER JOIN sys.partitions AS p
ON i.[object_id] = p.[object_id] AND i.index_id = p.index_id
INNER JOIN sys.allocation_units AS a
ON p.partition_id = a.container_id
WHERE i.[object_id] = OBJECT_ID(@TableName, N'U')
GROUP BY i.name
ORDER BY i.name;
答案 7 :(得分:0)
有一个扩展存储过程sp_spaceused
可以获取此信息。从数据字典中做到这一点相当令人费解,但This link粉丝到一个执行它的脚本。 This stackoverflow question对于可用于构建城市规划的表和索引大小估计的基础数据结构有一些信息。
答案 8 :(得分:0)
此查询来自另外两个答案:
Get size of all tables in database
How to find largest objects in a SQL Server database?
,但我将此增强为通用。它使用sys.objects
字典:
SELECT
s.NAME as SCHEMA_NAME,
t.NAME AS OBJ_NAME,
t.type_desc as OBJ_TYPE,
i.name as indexName,
sum(p.rows) as RowCounts,
sum(a.total_pages) as TotalPages,
sum(a.used_pages) as UsedPages,
sum(a.data_pages) as DataPages,
(sum(a.total_pages) * 8) / 1024 as TotalSpaceMB,
(sum(a.used_pages) * 8) / 1024 as UsedSpaceMB,
(sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM
sys.objects t
INNER JOIN
sys.schemas s ON t.SCHEMA_ID = s.SCHEMA_ID
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' AND
i.OBJECT_ID > 255 AND
i.index_id <= 1
GROUP BY
s.NAME, t.NAME, t.type_desc, i.object_id, i.index_id, i.name
ORDER BY
sum(a.total_pages) DESC
;
答案 9 :(得分:0)
要查看单个表(及其索引)的存储数据:
exec sp_spaceused MyTable