Question

我对python非常陌生，我只是尝试了一些简单的程序，我目前正在尝试制作一个程序，在用户输入的间隔内显示所有偶数。我有它工作，但我认为我有一个逻辑错误，我无法弄清楚。如果我使用间隔2-8我的程序将打印

我的代码是：

startingnumber = int(input("Please enter a starting even number:"))
if startingnumber%2==0:
    endingnumber = int(input("Please enter an ending number:"))
else:
    print("Please eneter an even number")

for num in range(startingnumber,endingnumber):
        for i in range(num):
            if (num%2) ==0:
                print(num)

有人可以尝试帮助发现我的错误吗？感谢

Answer 1

for num in range(startingnumber,endingnumber):
            if (num%2) ==0:
                print(num)

你有一个你不需要的额外循环。

Answer 2

Just use a step of 2:

range(start, end, step)

#This is not suggestible way to code in Python, but it gives a better understanding


numbers = range(1,10)

even = []

for i in numbers:

     if i%2 == 0:

       even.append(i)
print (even)

Answer 3

而不是做

for num in range(startingnumber,endingnumber):

DO

for num in range(startingnumber+startingnumber%2,endingnumber+1,2):
    print(num)

使用范围显示间隔中的数字

3 个答案: