基于列的重复值检索行

Question

我想从我的表Card中检索数据。

table Card(
  MembershipNumber,
  EmbossLine,
  status,
  EmbossName
)

这样只返回那些具有重复MembershipNumber的行，即count大于1。 就像我有以下记录

(11,0321,'active','John')
(11,0322,'active','John')
(23,0350,'active','Mary')
(46,0383,'active','Fudge')
(46,0382,'active','Fudge')
(46,0381,'active','Fudge')

查询应返回除第三个以外的所有记录。有可能吗？

已编辑我得到了我的问题的答案。我有另一个问题。我想按status过滤行，但是当我运行以下查询时，我得不到所需的结果：

SELECT EmbossLine,Membershipnumber,status,embossname,*
FROM   (SELECT *,
               Count(MembershipNumber)OVER(partition BY EmbossName) AS cnt
        FROM   card) A
WHERE cnt > 1 AND status='E0'

在where子句中添加status之前，它完全正常。见图片

按状态

添加过滤后

Answer 1

使用Count() Over()窗口功能执行此操作。

SELECT *
FROM   (SELECT *,
               Count(MembershipNumber)OVER(partition BY EmbossName) AS cnt
        FROM   youurtable) A
WHERE  cnt > 1 

<强>演示

SELECT MembershipNumber,
       [status],
       EmbossName
FROM   (SELECT *,
               Count(MembershipNumber)OVER(partition BY EmbossName) AS cnt
        FROM   (VALUES (11.0321,'active','John'),
                       (11.0322,'active','John'),
                       (23.0350,'active','Mary'),
                       (46.0383,'active','Fudge'),
                       (46.0382,'active','Fudge'),
                       (46.0381,'active','Fudge')) tc (MembershipNumber, [status], EmbossName)) A
WHERE  cnt > 1 

Answer 2

SELECT * FROM CARD a WHERE
(SELECT COUNT(*) FROM CARD b WHERE b.MembershipNumber = a.MembershipNumber) > 1

应该这样做

Answer 3

Select c.* from card c
join (select MembershipNumber from table group by
        MembershipNumber having count(MembershipNumber) > 1) mem
on mem.MembershipNumber = c.MembershipNumber

或者

Select * from table where MembershipNumber in
(select MembershipNumber from table group by
        MembershipNumber having count(MembershipNumber) > 1)

Answer 4

在empbossname上找到重复项并获得结果

select t1.* from card as t1 inner join 
(select empbossname from card group by empbossname  having count(*)>1) as t2
on t1.empbossname =t2.empbossname