我遇到方法问题。因此,在一个方法中,我向用户询问名字,我想将该String存储在另一个方法中,然后让我的main方法调用存储String的方法。但我在存储该字符串时遇到了麻烦。我使用此代码:
static void GetStudentInformation()
{
Console.WriteLine("Enter the student's first name: ");
string firstName = Console.ReadLine();
}
static void PrintStudentDetails(string first)
{
Console.WriteLine("{0}", first);
}
public static void Main (string[] args){
GetStudentInformation();
}
因此,一旦输入名称,它应该存储在详细信息方法中,然后在main方法中调用。谢谢你提前帮助我。
答案 0 :(得分:5)
static string GetStudentInformation()
{
Console.WriteLine("Enter the student's first name: ");
return Console.ReadLine();
}
static void PrintStudentDetails(string first)
{
Console.WriteLine("{0}", first);
}
public static void Main (string[] args)
{
string firstName = GetStudentInformation();
PrintStudentDetails(firstName);
}
如果您需要从用户检索多个输入。您可以返回字符串列表(快速解决方案):
static List<string> GetStudentInformation()
{
List<string> studentInformation = new List<string>();
//first name
Console.WriteLine("Enter the student's first name: "));
studentInformation.Add(Console.ReadLine());
//last name
Console.WriteLine("Enter the student's last name: "));
studentInformation.Add(Console.ReadLine());
//more
return studentInformation;
}
static void PrintStudentDetails(List<string> studentInformation)
{
foreach (string info in studentInformation)
{
Console.WriteLine("{0}", info);
}
}
public static void Main (string[] args)
{
List<string> studentInformation = GetStudentInformation();
PrintStudentDetails(studentInformation);
}
或创建一个类来存储所有输入(更好的解决方案):
class Student
{
public string FirstName {get;set;}
public string LastName {get;set;}
}
static Student GetStudentInformation()
{
Student student = new Student();
//first name
Console.WriteLine("Enter the student's first name: "));
student.FirstName = Console.ReadLine();
//last name
Console.WriteLine("Enter the student's last name: "));
student.LastName = Console.ReadLine();
//more
return student;
}
static void PrintStudentDetails(Student student)
{
Console.WriteLine("{0}", student.FirstName);
Console.WriteLine("{0}", student.LastName);
}
public static void Main (string[] args)
{
Student student = GetStudentInformation();
PrintStudentDetails(student);
}
答案 1 :(得分:0)
Student.java
public class Student {
private String studentName;
public Student(String studentName) {
this.name = studentName;
}
public static String getStudentName() {
return studentName;
}
public static void setStudentName(String newName) {
studentName = newName;
}
然后你可以这样做:
Student aStudent = new Student(Console.ReadLine);
我知道这对于您的特定情况并不完全有效,但它只是为了显示您想要做的事情背后的基本逻辑。