Question

有没有办法使用连续的JOptionPane输入对话框提示用户连续的阵列输入存储？也许我不善于提问，所以请参考下面的例子......

  titleInputs[x] = JOptionPane.showInputDialog(null, "Please enter a book title, or zzz to    
      quit:");
  authorInputs[x] = JOptionPane.showInputDialog(null, "Please enter " + titleInputs[x] + "'s 
      author's last name, or zzz to quit: ")
  pageInputs[x] = JOptionPane.showInputDialog(null, "Please enter " + titleInputs[x] + "'s page 
      count, or zzz to quit: ")

你能找到第一个titleInput，然后是另一个inputDialog请求作者，最后是pageCount吗？同时参考您要查询的选择的初始标题？

以下是期望的结果：标题＃1 请输入标题：请输入＆＃34; title＆＃39; s＆＃34;作者：请输入＆＃34; title＆＃39; s＆＃34;页数：标题＃2 请输入标题：请输入＆＃34; title＆＃39; s＆＃34;作者：请输入＆＃34; title＆＃39; s＆＃34;页数： ......继续收集所有5个标题......

Answer 1

int x = 0;
string currTitle = "";
do
{
  currTitle = JOptionPane.showInputDialog(null, "Please enter a book title, or zzz to quit:");
  if(!currTitle.equals("zzz"))
  {
    titleInputs[x] = currTitle;
    authorInputs[x] = JOptionPane.showInputDialog(null, "Please enter " + titleInputs[x] + "'s author's last name: ");
    pageInputs[x] = JOptionPane.showInputDialog(null, "Please enter " + titleInputs[x] + "'s page count: ");
    x = x+1;
  }
} while(!currTitle.equals("zzz")) //if you wanted, you could do: while(!currTitle.equals("zzz") && x < MAX_ARRAY_SIZE) ...obviously after declaring MAX_ARRAY_SIZE somewhere.

顺序用户输入存储在数组中

1 个答案: