Question

我有以下字符串（第1阶段）：

(Undergraduate level  <A HREF="blah=">PHYS 218</A> Minimum Grade of D) and (Undergraduate level  <A HREF="blah">MATH 152</A> Minimum Grade of D or Undergraduate level  <A HREF="/blah=">MATH 172</A> Minimum Grade of D or Undergraduate level  <A HREF="blah">MATH 251</A> Minimum Grade of D)

从此我去（第二阶段）：

(Undergraduate level PHYS 218 Minimum Grade of D) and (Undergraduate level MATH 152 Minimum Grade of D or Undergraduate level MATH 172 Minimum Grade of D or Undergraduate level MATH 251 Minimum Grade of D)

然后最终我想要的是（第3阶段）：

(PHYS 218) and (MATH 152 or MATH 172 or MATH 251)

目前我这样做的方式太可怕了。

我取第1阶段的字符串，完全删除所有a标签并合并剩下的文字。

然后我从a标签中取出课程编号，并将其放入上一步的字符串中，以进入第二阶段。

然后我在第二阶段查找课程，删除其左侧和右侧的所有内容，直到我点击(，)，or，and

有什么方法可以使用正则表达式或其他东西干净利落地做到这一点？谢谢。

Answer 1

x="""(Undergraduate level  <A HREF="blah=">PHYS 218</A> Minimum Grade of D) and (Undergraduate level  <A HREF="blah">MATH 152</A> Minimum Grade of D or Undergraduate level  <A HREF="/blah=">MATH 172</A> Minimum Grade of D or Undergraduate level  <A HREF="blah">MATH 251</A> Minimum Grade of D)"""
import re
print re.sub(r"<[^>]*>\s*|Undergraduate level\s*|Minimum Grade of [A-Z]+","",x)

如果格式始终是固定的并且不会发生太大变化，则可以使用re.sub执行此操作。

参见演示。

https://regex101.com/r/hF7zZ1/2

编辑：

如果文字正在改变，请试试这个

x="""(Undergraduate level  <A HREF="blah=">PHYS 218</A> Minimum Grade of D) and (Undergraduate level  <A HREF="blah">MATH 152</A> Minimum Grade of D or Undergraduate level  <A HREF="/blah=">MATH 172</A> Minimum Grade of D or Undergraduate level  <A HREF="blah">MATH 251</A> Minimum Grade of D)"""
import re
print "".join(re.findall(r"(\(|\)|\s*or\s*|\s*and\s*|(?<=>)[^<]*(?=<\/A>))",x))

Python正则表达式将外部文本与标签之间的文本组合在一起

1 个答案: