Java新手在这里,我正在尝试通过使用尽可能少的try ... catch语句来捕获抛出的异常。当我编译代码时,我收到了IllegalArgumentException
个错误,并且不确定如何通过使用try ... catch语句来解决这个问题。
我看了教程,看过其他的例子,但由于这对我来说是一个新概念,我仍然不确定如何使用try ... catch进行这个特定的练习。
public class Main extends Object {
public static void main(String [] args) {
tryGetMax();
tryRemove();
private static final void tryGetMax() {
int max = 0;
max = FunMethods.getMax((Integer[])null);
Integer[] numbers = new Integer[50];
Random rand = new Random();
for (int i = 0; i < 50; i++) {
numbers[i] = new Integer(rand.nextInt(500));
}
numbers[32] = null;
max = FunMethods.getMax(numbers);
numbers[32] = new Integer(rand.nextInt(500));
max = FunMethods.getMax(numbers);
}
练习的第二部分:
private static final void tryRemove() {
FunMethods.remove(null, 2);
Object[] someObjects = new Object[12];
someObjects[0] = "a string!";
someObjects[1] = new Integer(32);
someObjects[2] = new Float(42.5f);
someObjects[3] = "another string";
for (int i = 4; i < someObjects.length; i++) {
someObjects[i] = String.valueOf(i);
}
FunMethods.remove(someObjects, 12);
someObjects = FunMethods.remove(someObjects, 3);
答案 0 :(得分:0)
try{
//Code that can potentially throw an exception
} catch (IllegalArgumentException e){
//Code to run if exception is throw
}
将异常分配给变量e
,该变量具有可以调用的某些方法。
答案 1 :(得分:0)
好的,就在你应该public static void main(String[] args) {
的{{1}}下面try {
。然后,在main方法的末尾,您应该有} catch (IllegalArgumentException e) {
。在此之下,您应该拥有捕获该异常的代码,并}
。
现在这个:
public static void main(String [] args) {
tryGetMax();
tryRemove();
看起来像这样:
public static void main(String [] args) {
try {
tryGetMax();
tryRemove();
} catch(IllegalArgumentException e) {
//this code runs if e is thrown
}