Question

如何将json作为参数字符串传递。我尝试过如下传递json，但它会抛出AuthenticateUser: Invalid JSON primitive之类的错误。

let jsonString = "{\"user\":\"usr\",\"password\":\"pass\"}"

        var urlStr = "http://testserver/AuthenticateUser?data=\(jsonString)"


        var url = NSURL(string: urlStr)
        let request = NSMutableURLRequest(URL: url!)
        request.URL = url
        request.HTTPMethod = "POST"
        request.addValue("application/xml", forHTTPHeaderField: "Content-Type")
        request.addValue("application/xml", forHTTPHeaderField: "Accept")

        let task = NSURLSession.sharedSession().dataTaskWithRequest(request)
            {
                (data, response, error) in

                var error: NSError?
                if data != nil {
                    var reply = NSString(data: data!, encoding: NSUTF8StringEncoding)
                    println("reply >> \(reply)")
                }
        }
        task.resume()

Answer 1

请求初始化后添加此行：

request.HTTPBody = NSJSONSerialization.dataWithJSONObject(jsonString, options: nil, error: &err)

为json格式更新这些行：

request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")

参考：

POST with swift and API

http://jamesonquave.com/blog/making-a-post-request-in-swift/

Answer 2

我带你回答将json参数作为字符串传递给URL。

    var jsonString = "{\"user\":\"usr\",\"password\":\"pass\"}"
    if let data = jsonString.dataUsingEncoding(NSUTF8StringEncoding)    
    {
      var error: NSError?
      var json = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.allZeros, error: &error) as? NSDictionary
      if error != nil 
      {
        println(error)
      }
      else
      {
        println(json)
      }
      var strUser = json?.valueForKey("user") as String
      var strPassword = json?.valueForKey("password") as String

      println(strUser)
      println(strPassword)

      var url = "http://testserver/AuthenticateUser?data="
      var urlUserParameter = "user="
      var urlPasswordParameter = "&password="
      var appendString = "\(url)\(urlUserParameter)\(strUser)\(urlPasswordParameter)\(strPassword)"
               //OR
      var appendStringOne = url + urlUserParameter + strUser + urlPasswordParameter + strPassword

      println(appendString)
      println(appendStringOne)

    }

解释

  I converted JSON string to NSDictionary.
  Then i get value using key
  Finally i append all these string and now we have URL with parameters.

如何在swift中传递json字符串作为参数

2 个答案: