我有一个接受字符串数组作为参数的端点,但我无法使用alamofire。 我用postman测试我的端点并且它工作正常,即使在浏览器中,但是使用alamofire它失败并且只返回整个事物(好像我没有放任何参数)。
func getQuotes(String url){
//THIS CALL IS NOT WORKING. PARAMETERS ARE NOT SENT PROPERLY - FIX
let stringArray : [String] = ["4250_XSAU", "Test"]
let getQuoteParameters : Parameters = [
//"internal_symbols": stockInternalSymbols
"internal_symbols" : stringArray
]
print("attempting to get quotes on utility queue")
Alamofire.request(url, parameters: getQuoteParameters).responseJSON{ response in
print(response)
/* if (response.result.value != nil){
let jsonResponse = JSON(response.result.value!)
print(jsonResponse)
}
*/
}
}
我做错了吗?当我在我的浏览器或邮递员上访问url +"?internal_symbols = [" 4250_XSAU"," Test"]时,它运行正常。
我也试过设置我的" getQuoteParamaters"变量为
let getQuoteParameters : Parameters = [
"internal_symbols" : ["4250_XSAU", "Test"]
]
但它既不起作用......也应该是一样的。
只是澄清一下,这个请求完全忽略了我的参数,它应该将数组发送到我的后端。
答案 0 :(得分:2)
您可以简单地传递字符串数组,将其转换为JSON格式。如下面的示例代码所示:
var request = URLRequest(url: url)
request.httpMethod = "POST"
request.setValue("application/json", forHTTPHeaderField: "Content-Type")
let values = ["06786984572365", "06644857247565", "06649998782227"]
request.httpBody = try! JSONSerialization.data(withJSONObject: values)
Alamofire.request(request)
.responseJSON { response in
// do whatever you want here
switch response.result {
case .failure(let error):
print(error)
if let data = response.data, let responseString = String(data: data, encoding: .utf8) {
print(responseString)
}
case .success(let responseObject):
print(responseObject)
}
}
答案 1 :(得分:0)
请在您的请求中添加编码标准,例如JSONEncoding.default
func getQuotes(String url){
//THIS CALL IS NOT WORKING. PARAMETERS ARE NOT SENT PROPERLY - FIX
let stringArray : [String] = ["4250_XSAU", "Test"]
let getQuoteParameters : Parameters = [
//"internal_symbols": stockInternalSymbols
"internal_symbols" : stringArray
]
print("attempting to get quotes on utility queue")
Alamofire.request(url, method: .post, parameters: getQuoteParameters, encoding: JSONEncoding.default).responseJSON{ response in
print(response)
/* if (response.result.value != nil){
let jsonResponse = JSON(response.result.value!)
print(jsonResponse)
}
*/
}
感谢。
答案 2 :(得分:0)
我在Swift 3
的解决方案:
let text: [String] = ["location.branches.longitude", "location.branches.latitude"]
let params: Parameters = [
"_source": text
]