我非常感谢您在帖子中进一步了解:Finding Minimum Distance between Contours
我正在使用FindContours并根据需要获得多个轮廓。 问题是我想找到每个相邻对之间的最小距离, 例如黄色轮廓和深绿色之间,深绿色和青色之间,青色和紫色之间。
我从上面的帖子中了解了一般方法。 但有人可以告诉我如何一个接一个地选择它们(自动)?
void thresh_function(int, void*)
{
Mat canny_output;
vector<vector<Point> > contours;
vector<Vec4i> hierarchy;
/// Detect edges using canny
Canny( roiImg, canny_output, threshold_value, threshold_value*2, 3 );
/// Find contours
findContours( canny_output, contours, hierarchy, CV_RETR_TREE, CV_CHAIN_APPROX_SIMPLE, Point(0, 0) );
/// Draw contours
Mat drawing = Mat::zeros( canny_output.size(), CV_8UC3 );
for( int i = 0; i< contours.size(); i++ )
{
Scalar color = Scalar( rng.uniform(0, 255), rng.uniform(0,255), rng.uniform(0,255) );
drawContours( drawing, contours, i, color, 2, 8, hierarchy, 0, Point() );//Scalar(255,255,255)
}
erode(drawing,drawing,erodeElement2);
erode(drawing,drawing,erodeElement1);
dilate(drawing,drawing,dilateElement);
/// Show in a window
//namedWindow( "Contours", CV_WINDOW_AUTOSIZE );
resize(drawing, enlargeD0, Size(), 2, 2, CV_INTER_CUBIC);
done = 1;
imshow("Contours", enlargeD0);
}
答案 0 :(得分:2)
vector<vector<Point> > all_contours;
...
findContours(... all_contours ... CV_CHAIN_APPROX_NONE ...);
...
// Remove small contours
int minSize = 20;
vector<vector<Point> > contours;
contours.reserve(all_contours.size());
for(int i=0; i<all_contours.size(); ++i)
{
if(all_contours[i].size() > minSize)
{
contours.push_back(all_contours[i]);
}
}
Mat1f dist(contours.size(), contours.size(), 0.f);
for(int i=0; i<contours.size()-1; ++i)
{
const vector<Point>& firstContour = contours[i];
for(int j=i+1; j<contours.size(); ++j)
{
const vector<Point>& secondContour = contours[j];
float d = compute_pairwise_distance(firstContour, secondContour); // You should implement this
dist(i,j) = d;
dist(j,i) = d; // distance from first to second is equal
// to distance from second to first
}
}
// Now dist contains the pairwise distances between i-th and j-th contours