Question

我的名字是Adriel，我是网站和编程的新手。无论如何，我需要一些帮助和指导。我将在C中创建一个程序，允许用户输入最多5000个考试成绩。然后给用户5个选项以获得平均成绩，将所有考试从高到低显示，将考试上调5或下调5 AND 我不能做的是显示分数和获得的次数。

这是我的代码：

main() {

    //Declared variables
    char choice;
    int i, j, a, n;
    int examScore = 0, HIGH = 0, LOW = 0, AVG = 0, count = 0, sum = 0, scoreCount = 0;
    int highlow[5000], highExam, lowExam;

    do{//Begin do while #1
        CLS;
        FLUSH;
        printf("=========================\n");
        printf("===== Score program =====\n");
        printf("=========================\n");
        printf("A. Exam scores\n");
        printf("B. Exams average\n");
        printf("C. Exam score High - Low\n");
        printf("D. Times scores obtained\n");
        printf("E. Curved up 5 pts\n");
        printf("F. Curved down 5 pts\n");
        printf("Q. Exit program\n");
        printf("=========================\n");
        printf("Enter your choice: ");
        scanf(" %c", &choice);
        choice = toupper(choice);
        switch (choice){//Begin switch
        case 'A':
            CLS;
            printf("Please Enter The Number of exams:\n");
            scanf("%d", &n);

            printf("Please Enter %d Numbers\n", n);
            for (i = 0; i < n; i++){
                scanf("%d", &highlow[i]);
            }//end for loop
            highlow[examScore];
            count++;
            sum = sum + examScore;
            AVG = sum / count;
            highExam = examScore + 5;
            lowExam = examScore - 5;
            CLS;
            for (i = 0; i < n; i++)
            {
                for (j = i + 1; j<n; ++j)
                {
                    if (highlow[i]<highlow[j])
                    {
                        a = highlow[i];
                        highlow[i] = highlow[j];
                        highlow[j] = a;
                    }
                }
            }


            PAUSE;
            break;

        case 'B':
            CLS;
            printf("Exam average is: %i\n", AVG);
            PAUSE;
            break;

        case 'C':
            CLS;
            printf("The numbers arranged in descending order are given below\n");

            for (i = 0; i < n; ++i)

            {

                printf("%i\n", highlow[i]);
            }
            PAUSE;
            break;

        case 'D':
            CLS;
            printf("Amount of times scored was obtained: %i-%i\n", examScore, count);
            PAUSE;
            break;

        case 'E':
            CLS;
        //  printf("Exam scores curved up by 5 pts: %i\n", highExam);
            PAUSE;
            break;

        case 'F':
            CLS;
        //  printf("Exam scores curved down by 5 pts: %i\n", lowExam);
            PAUSE;
            break;

        case 'Q':
            CLS;
            printf("Quitting program. Goodbye.\n");
            PAUSE;
            break;

        default:
            printf("- Invalid entry -\n");
            PAUSE;
            break;

        }//End switch

    } while (choice != 'Q');//End do while #1


}//End main

你可能已经看到我还远没有完成，但其他部分对我来说并不是一个大问题。任何帮助和建议都会非常感激。

Answer 1

为什么计算highlow数组中每个分数的次数如此困难？

我想到了一种不同的方法，直到我注意到你有一个排序的分数数组，所以任何重复的分数将彼此相邻。应该很容易看到highlow[0]的值，然后将其与highlow[1]进行比较，看看highlow[0]是否重复。你只是这样做，直到你发现下一个不是重复，然后你开始寻找下一个数字的重复。

显示获得每个分数的分数和次数

1 个答案: