Question

因此，程序会收集指定的分数，然后按升序显示，然后应显示平均分数。但是现在，它只显示第一个分数，并除以分数。如何才能正确显示？

#include <iostream>
#include <iomanip>

using namespace std;

void sortArray(int*, int);
double getAverage(int*, int);


int main()
{
int *scores;
int num_Tests;

cout << "How many test scores would you like to enter?" << endl;
cin  >> num_Tests;

scores = new int[num_Tests];

cout << "\nEnter score number (do not use negative numbers):\n";
    for (int count = 0; count < num_Tests; count++)
    {
    cout << count + 1 << ". ";
    cin >> scores[count];
    }

sortArray(scores, num_Tests);

cout << "\n\n";
cout << "\n\n________________________________________________________________________________" << endl;
cout << "Test Score List (in ascending order)" << endl;
cout << "________________________________________________________________________________" << endl;

    for (int count = 0; count < num_Tests; count++)
    {
    cout << count + 1 << ". ";
    cout << scores[count] << endl;
    }

cout << "\nAverage test score: " << getAverage(scores, num_Tests) << endl;

return 0;
}

double getAverage(int *scores, int size)
{
double ttlScore = 0.0;
double avgScore = 0.0;

ttlScore += *scores;
avgScore = ttlScore / size;

return avgScore;
}

void sortArray(int *scores, int size)
{
int temp;
bool swap;

    do
    { swap = false;
        for (int count = 0; count < (size - 1); count++)
        {
            if (scores[count] < scores[count + 1])
            {
            temp = scores[count];
            scores[count] = scores[count + 1];
            scores[count + 1] = temp;
            swap = true;
            }
        }
    } while (swap);
}

Answer 1

getAverage逻辑不正确。您只是添加第一个号码。添加如下：

   double getAverage(int *scores, int size)
   {
     double ttlScore = 0.0;
     double avgScore = 0.0;

     for(int i=0;i<size;i++) 
     { 
      ttlScore += *(scores+i);
     }
      avgScore = ttlScore / size;
      return avgScore;
   }

Answer 2

你需要遍历你的得分数组来添加它们，你不能只做ttlScore += *scores，它必须是ttlScore += scores[index]

示例：

double getAverage(int *scores, int size)
{
    double ttlScore = 0.0;

    for (int i = 0; i < size; i++)
    {
        ttlScore += scores[i];
    }

    return ttlScore / size;
}

Answer 3

*得分引用数组的开头。您需要将指向的数组的所有值相加：

for (int i=0; i < size; i++)
{
ttlScore += scores[i];
}
avgScore = ttlScore / size;

return avgScore;

Answer 4

我认为这些会对你有帮助，

double getAverage（int * scores，int size）{

 int    i, sum = 0;       
 double avg;          

for (i = 0; i < size; ++i)
  {
   sum += scores[i];
   }

 avg = (double)sum / size;

 return avg;

}

尝试让我知道是否有任何问题？

Answer 5

我是编程新手，但这就是我所拥有的。

//average function

double average(int* pnData)

{

     double result;

     int sum = 0;     //declare and initialize our variables
     int count = 0;

     for (int i = 0; i < pnData[i]; i++)
     {
          sum += pnData[i];  //sum = sum + elements of our array
          count++;           //increment count
     }//end of for loop

     result = sum/(double)count;
     return result;
}//end of function average

这样您就不必知道数组的长度或数量了。

（c ++）计算平均回报的函数（第一分数/总分数）？

5 个答案: