如何找到集合之间的交集

Question

假设我们有一个容器列表，每个容器都是一个对象。 在每个容器中都有一些对象。

我们如何找到所有重复的对象，这些对象在两个或多个容器中共享？

每个容器都有一个ID，Name，对象列表作为属性。 每个对象都有一个ID和名称。

请看图片：

结果应该是：

-------------
Object1.Name    
Object2.Name    
Object3.Name
-------------

我使用了一些不正确的代码

  public class Container
    {
        public string ID;
        public string Name;
        public string Top, Left, Right, Bottom;
        public List<ObjectX> Objects = new List<ObjectX>();

    }



public class ObjectX
    {
        public string ID;
        public string Name;
        public string Top, Left, Right, Bottom;

    }


 List<Container> AllBoundaries = new List<Container>();
            List<ObjectX> all_components = new List<ObjectX>();
            Container b1 = new Container();
            b1.Name = "Boundary1";
            b1.ID = "1";
            AllBoundaries.Add(b1);

            Container b2 = new Container();
            b2.Name = "Boundary2";
            b2.ID = "2";
            AllBoundaries.Add(b2);

            Container b3 = new Container();
            b3.Name = "Boundary3";
            b3.ID = "3";
            AllBoundaries.Add(b3);
//----------------------------------------------------------------------------------------
            ObjectX c1 = new ObjectX();
            c1.ID = "1";
            c1.Name = "c1";
            b1.Objects.Add(c1);

            ObjectX c2 = new ObjectX();
            c2.ID = "2";
            c2.Name = "c2";
            b1.Objects.Add(c2);

            ObjectX c3 = new ObjectX();
            c3.ID = "3";
            c3.Name = "c3";
            b1.Objects.Add(c3);

            ObjectX c22 = new ObjectX();
            c22.ID = "2";
            c2.Name = "c2";
            b2.Objects.Add(c2);

            foreach (Container   bx1 in  AllBoundaries )
            {

                foreach (Container bx2 in AllBoundaries)
                {
                    for (int i = 1; i < bx2.Objects.Count; i++)

                        if (bx1.ID != bx2.ID)
                        {
                            List<ObjectX> query = bx1.Objects.FindAll(bx => bx.Name == bx2.Objects[i].Name);
                            Console.WriteLine(bx2.Objects[i].Name + " Distributed");
                            bx2.Objects.Remove(bx2.Objects[i]);
                        }

                }
            }

但是这给了我1到9的所有对象，这是不正确的。

Answer 1

假设您有一个容器集合，您可以执行以下操作：

var item = from c in containers
           from o in c.Objects
           group c.ContainerName by o into g
           where g.Distinct().Count() > 1
           select g.Key;