我怀疑这是不可能的,但我还没有看到明确的否定。
我目前的(工作)实施如下:
public static Main(param args[])
{
dynamic Repository = GetRepository();
var query = (Repository.QueryUser() as IQueryable<User>)
.Where(user => user.Name.ToLower().Contains("jack"));
}
public static dynamic GetRepository()
{
dynamic repo = new System.Dynamic.ExpandoObject();
repo.QueryUser = new [] { new User() { Name = "Jack Sparrow"}}.AsQueryable<User>();
return repo;
}
为了更好地使用Generic方法模拟(常用的)Repository接口,我想实现如下内容:
public interface IRepository
{
IQueryable<T> Query<T>();
}
public static Main(param args[])
{
IRepository Repository = GetRepository(); // return a dynamic
var query = Repository.Query<User>()
.Where(user => user.Name.ToLower().Contains("jack"));
}
public static dynamic GetRepository()
{
dynamic repo = new System.Dynamic.ExpandoObject();
// the issue is on the following line
repo.Query<User> = new [] {
new User() {
Name = "Jack Sparrow"
}
}.AsQueryable<User>();
return repo;
}
是否有可能的解决方法(使用System.Dynamic命名空间中的某些内容)?
答案 0 :(得分:4)
我对此表示怀疑,您只能获取或设置ExpandoObject
的“属性”(或events),而不是定义新方法。如果您想这样做,则必须创建自己的动态对象,并为其添加自己的成员。
但是我觉得我必须这样说,为什么不只是使用构图呢?创建一个添加方法的类,并为expando创建一个属性。
class MyClass
{
public dynamic Expando { get; } = new ExpandoObject();
public void MyMethod<T>() { }
}
如果您绝对想要这样做,可以在ExpandoObject
上创建一个动态元对象包装器的动态对象。然后在包装器中,将所有绑定转发给您的动态对象,将所有其他绑定转发给expando。该对象将是您使用expando的功能定义的对象。
如,
// be sure to explicitly implement IDictionary<string, object>
// if needed forwarding all calls to the expando
class ExtendedExpandoObject : IDynamicMetaObjectProvider
{
DynamicMetaObject IDynamicMetaObjectProvider.GetMetaObject(Expression parameter) => new MyMetaObject(parameter, this);
public ExtendedExpandoObject(ExpandoObject expandoObject = null)
{
Value = expandoObject ?? new ExpandoObject();
}
public ExpandoObject Value { get; }
// the new methods
public string GetMessage() => "GOT IT!";
public string GetTypeName<T>() => typeof(T).Name;
// be sure to implement methods to combine results (e.g., GetDynamicMemberNames())
class MyMetaObject : DynamicMetaObjectWrapper
{
public MyMetaObject(Expression parameter, ExtendedExpandoObject value)
: base(new DynamicMetaObject(parameter, BindingRestrictions.Empty, value))
{
var valueParameter = Expression.Property(
Expression.Convert(parameter, typeof(ExtendedExpandoObject)),
"Value"
);
IDynamicMetaObjectProvider provider = value.Value;
ValueMetaObject = provider.GetMetaObject(valueParameter);
}
protected DynamicMetaObject ValueMetaObject { get; }
public override DynamicMetaObject BindGetMember(GetMemberBinder binder)
{
if (IsMember(binder.Name))
return base.BindGetMember(binder);
return ValueMetaObject.BindGetMember(binder);
}
public override DynamicMetaObject BindSetMember(SetMemberBinder binder, DynamicMetaObject value)
{
if (IsMember(binder.Name))
return base.BindSetMember(binder, value);
return ValueMetaObject.BindSetMember(binder, value);
}
private bool IsMember(string name) => typeof(ExtendedExpandoObject).GetMember(name).Any();
}
}
有了这个,你可以像使用任何expando对象一样使用它。
dynamic expando = new ExtendedExpandoObject();
Console.WriteLine(expando.Value); // the original expando
expando.Length = 12; // set a new property on the expando
Console.WriteLine(expando.Length); // get a property on the expando
Console.WriteLine(expando.GetMessage()); // call the new method
Console.WriteLine(expando.GetTypeName<ExtendedExpandoObject>()); // call the generic method
Console.WriteLine(expando.Value.Length); // get the property on the original expando
你只需要DynamicMetaObjectWrapper:
public abstract class DynamicMetaObjectWrapper : DynamicMetaObject
{
protected DynamicMetaObjectWrapper(DynamicMetaObject metaObject)
: base(metaObject.Expression, metaObject.Restrictions, metaObject.Value)
{
BaseMetaObject = metaObject;
}
public DynamicMetaObject BaseMetaObject { get; }
public override DynamicMetaObject BindBinaryOperation(BinaryOperationBinder binder, DynamicMetaObject arg) => BaseMetaObject.BindBinaryOperation(binder, arg);
public override DynamicMetaObject BindConvert(ConvertBinder binder) => BaseMetaObject.BindConvert(binder);
public override DynamicMetaObject BindCreateInstance(CreateInstanceBinder binder, DynamicMetaObject[] args) => BaseMetaObject.BindCreateInstance(binder, args);
public override DynamicMetaObject BindDeleteIndex(DeleteIndexBinder binder, DynamicMetaObject[] indexes) => BaseMetaObject.BindDeleteIndex(binder, indexes);
public override DynamicMetaObject BindDeleteMember(DeleteMemberBinder binder) => BaseMetaObject.BindDeleteMember(binder);
public override DynamicMetaObject BindGetIndex(GetIndexBinder binder, DynamicMetaObject[] indexes) => BaseMetaObject.BindGetIndex(binder, indexes);
public override DynamicMetaObject BindGetMember(GetMemberBinder binder) => BaseMetaObject.BindGetMember(binder);
public override DynamicMetaObject BindInvoke(InvokeBinder binder, DynamicMetaObject[] args) => BaseMetaObject.BindInvoke(binder, args);
public override DynamicMetaObject BindInvokeMember(InvokeMemberBinder binder, DynamicMetaObject[] args) => BaseMetaObject.BindInvokeMember(binder, args);
public override DynamicMetaObject BindSetIndex(SetIndexBinder binder, DynamicMetaObject[] indexes, DynamicMetaObject value) => BaseMetaObject.BindSetIndex(binder, indexes, value);
public override DynamicMetaObject BindSetMember(SetMemberBinder binder, DynamicMetaObject value) => BaseMetaObject.BindSetMember(binder, value);
public override DynamicMetaObject BindUnaryOperation(UnaryOperationBinder binder) => BaseMetaObject.BindUnaryOperation(binder);
public override IEnumerable<string> GetDynamicMemberNames() => BaseMetaObject.GetDynamicMemberNames();
}
答案 1 :(得分:4)
您假设的expando对象实现不“满足”接口;它没有可以称为Query<T>
或Query<Foo>()
的通用Query<Bar>()
方法。它只有一个非通用的Query()
方法,它将返回IQueryable<User>
。也就是说,无论如何,Query<T>
似乎都不合理,尤其是没有类型约束。
我建议使用非通用方法,如QueryUsers
,QueryFoos
等,或者使用IRepository<T>
接口指定IQueryable<T> Query()
方法。以下是如何使用Impromptu-Interface库实现后一种方法:
using ImpromptuInterface;
using ImpromptuInterface.Dynamic;
using System.Linq;
public interface IRepository<T>
{
IQueryable<T> Query();
}
public class User
{
public string Name { get; set; }
}
public class Program
{
public static void Main(params string[] args)
{
IRepository<User> repo = GetUserRepository(); // dynamically construct user repository
var query = repo.Query()
.Where(user => user.Name.ToLower().Contains("jack"));
}
public static IRepository<User> GetUserRepository()
{
var repo = new
{
Query = Return<IQueryable<User>>.Arguments(() => new[] {
new User() {
Name = "Jack Sparrow"
}
}.AsQueryable())
}.ActLike<IRepository<User>>();
return repo;
}
}
使用这种方法,您的具体存储库只会为每个实际上是模型类型的IRepository<T>
实现T
接口。