Question

如何在MFC中声明需要CPoint参数的标准构造函数，例如

class CObj {
public:
    CObj(CPoint pt = ???, float x = 10.0f, int n = 10);
    ...

我试过

CObj(CPoint pt = (10,10), float x = 10.0f, int n = 10);

编译得很好，但只有pt.x得到值10而pt.y变为0。

谢谢，RS

Answer 1

我相信这样的事情应该有效：

CObj(Cpoint pt = CPoint(10,10), float x = 10.0f, int n = 10);

编辑：这似乎对我有用：

#include <iostream>

struct CPoint { 
    int x, y;
    CPoint(int x_, int y_) : x(x_), y(y_) {}
};

class CObj { 
   CPoint p;
public:
   CObj(CPoint pt = CPoint(10,10), float x = 10.0f, int n = 10) : p(pt) {
       std::cout << "x.x = " << p.x << "\tx.y = " << p.y << std::endl;
   }
};

int main() { 
    CObj x;
    return 0;
}

结果：

x.x = 10        x.y = 10

MFC中具有CPoint参数的标准构造函数

1 个答案: