Question

如何将存储电话号码的变量分配给按钮以拨打该号码？

我正在使用Swift。这是我的代码：

func base() {

    var myBase = sharedDefaults!.objectForKey("base") as? String

    if myBase != nil {
        if myBase == "FRA" {
            titleLabel.text = "FRANKFURT"
            adressLabel.text = "some adress"
            var phone = "+49123456 69 69804616"
            coorPhone.setTitle("Duty Desk : \(phone)", forState: .Normal)
            logoImage.image = UIImage(named: "flaggermany")

        } else if myBase == "LHR" {
            titleLabel.text = "LONDON"
            adressLabel.text = "some adress"
            var phone = "+44123456"

            coorPhone.setTitle("Duty Desk : \(phone)", forState: .Normal)

            logoImage.image = UIImage(named: "flaguk")

        }
    }

    @IBAction func phoneButtonPressed(sender: AnyObject) {
        // let telUrlString = "tel://" + phone
        // UIApplication.sharedApplication().openURL(NSURL(string: "\      (telUrlString)")!)
    }

Answer 1

您可以通过在类声明的下方声明它，将phone变量声明为您班级的全局变量，如下所示：

class ViewController: UIViewController {

     let sharedDefaults = NSUserDefaults.standardUserDefaults()
     var phone = ""

}

通过这种方式声明，您可以在班级的任何位置访问它，现在您可以在函数中以这种方式为其赋值：

func base() {

    var myBase = sharedDefaults.objectForKey("base") as? String

    if myBase != nil {
        if myBase == "FRA" {

            titleLabel.text = "FRANKFURT"
            adressLabel.text = "some adress"
            phone = "+49123456 69 69804616"
            coorPhone.setTitle("Duty Desk : \(phone)", forState: .Normal)
            logoImage.image = UIImage(named: "flaggermany")


        }
        else if myBase == "LHR" {
            titleLabel.text = "LONDON"
            adressLabel.text = "some adress"
            phone = "+44123456"
            coorPhone.setTitle("Duty Desk : \(phone)", forState: .Normal)
            logoImage.image = UIImage(named: "flaguk")

        }
    }
}

之后你可以用这种方式进入另一个功能：

@IBAction func phoneButtonPressed(sender: AnyObject) {

    if let url = NSURL(string: "tel://\(phone)") {
        UIApplication.sharedApplication().openURL(url)
    }
}

希望这会对你有所帮助。

Answer 2

@IBAction func phoneButtonPressed(sender: UIButton) {
    if let url = NSURL(string: "tel://\(phone)") {
        UIApplication.sharedApplication().openURL(url)
    }
}

如果在viewController.swift文件的顶部定义变量phone（在类调用之下），则可以使用此代码，这样就可以在函数中访问它。

用Swift拨打电话号码

2 个答案: